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Pachacha [2.7K]
3 years ago
11

James conducted an experiment with 4 possible outcomes. He determined that the experimental probability of event A happening is

10 out of 50. The theoretical probability of event A happening is 1 out of 4. Which action is most likely to cause the experimental probability and theoretical probabilities for each event in the experiment to become closer? removing the last 10 trials from the experimental data completing the experiment many more times and combining the results to the trials already done including a fifth possible outcome performing the experiment again, stopping immediately after each event occurs once
Mathematics
2 answers:
Ganezh [65]3 years ago
8 0

Answer:

Completing the experiment a few more times and combining the results to the trails already done.

MAVERICK [17]3 years ago
5 0

Answer:

Completing the experiment a few more times and combining the results to the trails already done.

Step-by-step explanation:

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The Perimeter Answer is 12 cm
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. Exam scores for a large introductory statistics class follow an approximate normal distribution with an average score of 56 an
Andru [333]

Answer:

0.1% probability that the average score of a random sample of 20 students exceeds 59.5.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 56, \sigma = 5, n = 20, s = \frac{5}{\sqrt{20}} = 1.12

What is the probability that the average score of a random sample of 20 students exceeds 59.5?

This is 1 subtracted by the pvalue of Z when X = 59.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{59.5 - 56}{1.12}

Z = 3.1

Z = 3.1 has a pvalue of 0.9990.

So there is a 1-0.9990 = 0.001 = 0.1% probability that the average score of a random sample of 20 students exceeds 59.5.

3 0
3 years ago
Help is needed! Desperate
Bogdan [553]
Sorry I don't know that question.
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3 years ago
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Which statement about 2(x+4) is true. Possible answers: :2(x+4) is a quotient :2(x+4)is a product of three factors :2(x+4)has 4
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4 0
2 years ago
Read 2 more answers
a) The weekly wages of employees of Volta gold are normally distributed about a mean of $1,250 with a standard deviation of $120
Fantom [35]

Answer:

0.7102

0.8943

0.3696

Step - by - Step Explanation :

A.) Between $1320 and $970

P(Z < 1300) - P(Z < 970)

find the Zscore of each scores and their corresponding probability uinag the standard distribution table :

P(Z < (x - μ) /σ) - P(Z < (x - μ) / σ))

P(Z < (1320 - 1250) /120) - P(Z < (970 - 1250) / 120))

P(Z < 0.5833) - P(Z < - 2.333)

0.7200 - 0.0098 = 0.7102 (Standard

=0.7102

B.)Under 1400

x = 1400

P(Z < 400)

P(Z < (x - μ) /σ)

P(Z < (1400 - 1250) /120)

P(Z < 1.25) = 0.8943

C.) Over 1290

P(Z > 1290)

P(Z < (x - μ) /σ)

P(Z > (1290 - 1250) /120 = 0.3333

P(Z > z) = 1 - P(Z < 0.3333) = P(Z < 0.3333) = 0.6304

P(Z > 0.3333) = 1 - 0.6304 = 0.3696

4 0
3 years ago
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