First off, your chances of red are not really 50-50. You are overlooking the 0 slot or the 00 slot which are green. So, chances of red are 18 in 37 (0 slot) or 38 (0 and 00 slots). With a betting machine, the odds does not change no trouble what has occurred before. Think through the simplest circumstance, a coin toss. If I toss heads 10 times one after the other, the chances of tails about to happen on the next toss are still on a 50-50. A betting machine has no ability, no plan, and no past.
Chances (0 slot) that you success on red are 18 out of 37 (18 red slots), but likelihoods of losing are 19 out of 37 (18 black plus 0). For the wheel with both a 0 and 0-0 slot, the odds are poorer. You chances of red are 18 out of 38 (18 red slots win), and down are 20 out of 38 (18 black plus 0 and 00). It does not really matter on how long you play there, the probabilities would always continue the same on every spin. The lengthier you play, the more thoroughly you will tie the chances with a total net loss of that portion of a percent in accord of the house. 18 winning red slots and either 19 or 20 losing slots.
Answer:
The numbers will be "11 and 12".
i believe
Step-by-step explanation:
x(x + 1) > x + x + 1 + 109 where x and x+1 are the 2 numbers.
x^2 + x > 2x + 110
x^2 - x - 110 > 0
(x - 11)(x + 10) > 0 The critical values are 11 and -10 but number must be natural
So the value of x is 11
The numbers are 11 and 12
Answer:
P'(1, 1), Q'(2, 2), R'(4, 1)
Step-by-step explanation:
The dilation factor multiplies each coordinate value, so ...
P' = (1/2)P = (2/2, 2/2) = (1, 1)
Q' = (1/2)Q = (4/2, 4/2) = (2, 2)
R' = (1/2)R = (8/2, 2/2) = (4, 1)
Each point is half as far from the origin as the original. Here, all of the PQR coordinates are even numbers, so dividing them by 2 is about as easy as it gets.
