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3 years ago

Which expression is equal to a + (b + c)?

Mathematics

2 answers:

stellarik [79]3 years ago

7 0

A is the correct answer

WINSTONCH [101]3 years ago

6 0

Hello there.

a. (a + b) + c

Which expression is equal to a + (b + c)?

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Cindy has 6 identical pink candies and 8 identical green candies. Find the number of ways that Cindy can line up her candies in

Daniel [21]

Answer:

175 ways

Step-by-step explanation:

Form a partition into 2 or 3 parts and the number of ways.

Pink candies

[1,5](2) , [2,4](2) , [3,3](1) , [1,4](3), [1,2,3](6) , [2,2,2](1)

Green candies

[1,7](2) , [2,6](2) , [3,5](2) , [4,4](1) , [1,1,6](3) , [1,2,5](6) , [1,3,4](6) , ,[2,2,4](3) , [2,3,3](3)

Number of ways will be:

(2+2+1) (2+6+6+3+3) + (3+6+1)(2+2+2+1)

Number of ways =( 5×21) + (10×7) = 175ways

4 0

3 years ago

How do you solve 4(8x+5)

alexandr1967 [171]

Answer:

32x+20

Step-by-step explanation:

4*8x+4*5=

32x+20

3 0

3 years ago

Read 2 more answers

Find the slope: x + 7y = 21

Aleksandr [31]

Answer: 1/7

Step-by-step explanation:

solve for y

7 0

3 years ago

Find the square root. -√1/9

harina [27]

Answer:

-1/9

that's the answer.

BRAINLIEST PLEASE

4 0

3 years ago

Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the

Rama09 [41]

Question:

Britney throws an object straight up into the air with an initial velocity of 27 ft/s from a platform that is 10 ft above the ground. Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the object to hit the ground?

1s 2s 3s 4s

Answer:

It takes 2 seconds for object to hit the ground

Solution:

The given equation is:

$h(t) = -16t^2 + v_0t+h_0$

Initial velocity = 27 feet/sec

$h_0 = 10\ feet$

Therefore,

$h(t) = -16t^2 +27t+10$

At the point the object hits the ground, h(t) = 0

$-16t^2 +27t+10 = 0\\\\16t^2-27t-10=0$

Solve by quadratic formula,

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=16,\:b=-27,\:c=-10:\quad \\\\t=\frac{-\left(-27\right)\pm \sqrt{\left(-27\right)^2-4\cdot \:16\left(-10\right)}}{2\cdot \:16}\\\\t = \frac{27 \pm \sqrt{1369}}{32}\\\\t = \frac{27 \pm 37}{32}\\\\We\ have\ two\ solutions\\\\t = \frac{27+37}{32}\\\\t = \frac{64}{32}\\\\t = 2\\\\And\\\\t = \frac{27-37}{32}\\\\t = -0.3125$

Ignore, negative value

Thus, it takes 2 seconds for object to hit the ground

7 0

3 years ago