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Paul [167]
3 years ago
7

Which expression is equal to a + (b + c)?

Mathematics
2 answers:
stellarik [79]3 years ago
7 0
A is the correct answer
WINSTONCH [101]3 years ago
6 0
Hello there.
<span>
a. (a + b) + c
</span>
Which expression is equal to a + (b + c)?
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Based only on the information given in the diagram, it is guaranteed that JKL ~ WXY.
Alika [10]

Answer:

Option A True

Step-by-step explanation:

we know that

The sum of the internal angles of  the triangle is equal to 180\°

<u>In the triangle JKL</u>

m∠L=180\°-90\°-27\°=63\°

so

The measurements of the angles of triangle JKL are 27\°-90\°-63\°

<u>In the triangle WXY</u>

m∠W=180\°-90\°-63\°=27\°

so

The measurements of the angles of triangle WXY are 27\°-90\°-63\°

therefore

Triangle JKL and triangle WXY are similar by AAA ( The AAA postulate states that if you can prove that all three angles of two triangles are congruent, you can prove the two triangles are similar)

6 0
3 years ago
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Rearrange y=1/2x+1 to make x the subject of the formula
Zinaida [17]
X/2+1=y  subtract 1 from both sides

x/2=y-1  multiply both sides by 2

x=2y-2
4 0
3 years ago
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Please help me solve ASAP!!
suter [353]

Answer:

gdfgdfgdfgggggdrgetert

Step-by-step explanation:

dfgdfgfdgdfgdfggggggggggggggddfg

6 0
3 years ago
Evaluate the expression for the given values of the variables. Under selected conditions, a sports car gets 14 mpg in city drivi
Degger [83]

Answer:

28 gallons

Step-by-step explanation:

We are given that a sports car gets 14mpg in city driving and 19mpg for highway.

The model G=\frac{1}{14} c+\frac{1}{19 }h

Where G=Amount of gasoline used (in gal) for c miles driven in the city and h miles driven on the high way.

Amount of gas used in 14 miles car  in the city driving=1 gal

Amount of gas used in 1 mile car  in the city driving=\frac{1}{14} gal

Amount of gas used in c miles car in the city driving =\frac{1}{14}c gal

Similarly, for  car driving on highway

Amount of gas used in h miles for car  driving on highway=\frac{1}{19}h

c=98 miles in the city

h=399 miles on the highway

We have to find the amount of gas used required to derive 98 miles in the city and 399 miles on the highway.

Substitute the value of c and h in the given expression

Then, G=\frac{1}{14}\times 98+\frac{1}{19}\times 399=7+21=28 gal

Hence, the amount of gas required to derive 98 miles in the city and 399 miles on the highway=28 gallons

6 0
3 years ago
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Lcm of 6 and 28 pls help<br>​
lara31 [8.8K]

Answer:

84

Step-by-step explanation:

4 0
3 years ago
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