Answer:
The empirical formula is C3H3O
Explanation:
Step 1: Data given
Suppose the mass of the molecule = 100 grams
The molecule contains:
65.5 % Carbon = 65.5 grams
5.5 % Hydrogen = 5.5 grams
29.0% Oxygen = 29.0 grams
Molar mass of C = 12 g/mol
Molar mass of H = 1.01 g/mol
Molar mass of O = 16 g/mol
Step 2: Calculate moles
Moles = mass / molar mass
Moles C = 65.5 grams / 12 g/mol = 5.46 moles
Moles H = 5.5 / 1.01 g/mol = 5.45 moles
Moles O = 29.0 grams / 16 g/mol = 1.8125 moles
Step 3: Calculate mol ratio
We divide by the smallest amount of moles
C: 5.46 / 1.8125 = 3
H = 5.45 / 1.8125 = 3
O = 1.8125/1.8125 = 1
The empirical formula is C3H3O
Answer:
1s2 2s2 2p6 3s2 3p6 4s2
shorthand: [Ar] 4s2
Explanation:
the end number values are exponents, so 1s^2
Answer:
(a) Perchloric acid (HClO₄)
(b) Nitric acid (HNO₃)
(c) Bromous acid (HBrO₂)
(d) Phosphoric Acid (H₃PO₄)
Explanation:
Acids are the species which furnish hydrogen ions in the solution. The other specie produced with the hydrogen ion is called its conjugate base.
Thus,
(a) Perchlorate (ClO₄⁻) ion:
The acid that furnish perchlorate ion is <u>perchloric acid (HClO₄)</u>.
(b) NO₃⁻ ion:
The acid that furnish NO₃⁻ ions is <u>Nitric acid (HNO₃)</u>.
(c) bromite (BrO₂⁻) ion:
The acid that furnish BrO₂⁻ ions is <u>Bromous acid (HBrO₂)</u>.
(d) H₂PO₄⁻ ion:
The acid that furnish H₂PO₄⁻ ions is <u>Phosphoric Acid (H₃PO₄)</u>.
735 torr = 1 atmosphere(atm)
Temperature in Kelvin = 273 + 35 = 308 K
Moles of Nitrogen gas = mass of N2 / molar mass of N2
= 35.4/28.014
= 1.26 moles
Using Ideal gas equation,
PV = nRT
1 x V = 1.26 x 0.082 x 308
V = 31.822 liters.
Hope this helps!
