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Nookie1986 [14]
4 years ago
7

Which of the following pairs of compounds would be most easily separated by thin layer chromatography: n-octyl alcohol and 1-oct

ene, hexadecane and octadecane, or chlorobenzene and bromobenzene?
A. hexadecane and octadecane
B. n-octyl alcohol and 1-octene
C. chlorobenzene and bromobenzene
Chemistry
1 answer:
Naddika [18.5K]4 years ago
6 0

Answer:

B. n-octyl alcohol and 1-octene

Explanation:

Thin-layer chromatography (TLC) is a chromatography technique used to separate non-volatile mixtures. The principle is that different compounds in the sample mixture travel at different rates due to the differences in interactions with stationary phase and due to the differences in solubility in the solvent. The principal chemical property for separation using this technique is molecular polarity

You can intuit than hexadecane and octadecane don't have big polarity differences, also chlorobenzene and bromobenzene haven't.

An alcohol as n-octyl alcohol has different polarity than an alkene as 1-octene.

Thus, using  thin layer chromatography is most easy to separate:

<em>B. n-octyl alcohol and 1-octene </em>

<em></em>

I hope it helps!

<em></em>

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: Calculate molar mass of the following compounds:
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Answer:

1. 58.5g/mol

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Now, if you watched the attached graph, you can see the solubility curve of many compounds in 100 g of water (or 100 mL of water). So, to know how many do you need in 50 mL, it's just the half.

So watching the curve, you can see that at 20 °C, we simply need between 35 g and 40 g. Let's just say we need 38 grams of NH4Cl to be dissolved in 100 mL of water.

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