Answer:Dimensions are of one corral is:
Length=50ft
Width= 37.5ft
Combined area=1875ft
Step-by-step explanation:
Let L= length
Let w = width
There are 3 pieces of fencing: 3L + 4w =300
W = (300 -3L)/ 4 ....equation 1
Combined area of the corrals is given by:
A= L × 2w...eq2
Put eq1 into eq2
A= L ×2(300-3L) /4
A= 1/2 (300 -3 L)^2
A= -(3/2)L^2 + 150
Using -b/2a to solve for L in the quadratic equation
-150/2(3/2) = (150×2)/(2×3)
L = 50ft
W= 300-3(50)/4
W=150/4=37.5ft
Combined are=50×37.5=1875ft
Answer:
33/16 hope this helps
Step-by-step explanation:
Answer:
<h2>see below</h2>
Step-by-step explanation:
<h3>to understand this</h3><h3>you need to know about:</h3>
<h3>given:</h3>
- f(x)=3x³-2x²-12x+8
- -a×-b=ab
- -a×b=-ab
- a²-b²=(a+b)(a-b)
<h3>to do:</h3>
- use factor theorem to show that (x+2) is a factor of f(x)
<h3>tips and formulas:</h3>
- When f(c)=0 then x−c is a factor of f(x)
<h3>let's solve:</h3>
according to the question
x+2=0
x=-2
therefore
we have proven that x+2 is a factor of 3x³-2x²-12x+8
let's factorise 3x³-2x²-12x+8
- factor out x²: x²(3x-2)-12x+8
- factor out -4: x²(3x-2)-4(3x-2)
- group: (x²-4)(3x-2)
- use a²-b² = (a+b)(a-b):
and
we are done
Ok. I do though, good luck