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Maurinko [17]
3 years ago
11

What multiplication fact Can be found by using the Arrays for 2 times 9 and 5 times 9

Mathematics
1 answer:
serg [7]3 years ago
8 0
An array is a visual drawing to be used in multiplication problems. For example; 1 × 2 is 2 and you draw it or visualize it like; 00
So the answer to your question would be...
000000000
000000000

000000000
000000000
000000000
000000000
000000000
000000000
000000000

The top is the array of how it would look like to your answer tour question. Also, another way to do this is (2 + 5) × 9 = 63 
And yasss your answer is 63.... ALSO

***!!! PLEASE give this a THANKS! ALSO the BRAINIEST ANSWER/QUESTION! :) :D =P =) =D
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*Quick answer please
Anastaziya [24]
He Paid $14 each share but lost $6 each share. 14-6= 8..... he sold 100 shares of stock for $8each. 100 divided by 8 =$12.50
6 0
3 years ago
GIVING BRAINLIEST+30 POINTS TO BEST ANSWER!! REMEMBER, FOLLOW DIRECTIONS!!
vitfil [10]

Answer:

Step-by-step explanation:

First, you would multiply 3x4 =12

next you would keep the denominator the same

last you would divide 8 by 12 10 get 1 3/8 for your answer

8 0
2 years ago
A large fish tank at an aquarium needs to be emptied so that it can be cleaned. When its
VikaD [51]

Answer:

The draining time when only the big drain is opened is 2.303 hours.

The draining time when only the small drain is opened is 5.303 hours.

Step-by-step explanation:

From Physics, we know that volume flow rate (\dot V), measured in liters per hour, is directly proportional to draining time (t), measured in hours. That is:

\dot V \propto \frac{1}{t}

\dot V = \frac{k}{t} (Eq. 1)

Where k is the proportionality constant, measured in liters.

From statement, we have the following three expressions:

(i) <em>Large and small drains are opened</em>

\dot V_{s}+\dot V_{l} = \frac{k}{2} (Eq. 2)

\frac{\dot V_{s}+\dot V_{l}}{k} = \frac{1}{2}

(ii) <em>Only the small drain is opened</em>

\dot V_{s} = \frac{k}{t_{l}+3} (Eq. 3)

\frac{\dot V_{s}}{k} = \frac{1}{t_{l}+3}

(iii) <em>Only the big drain is opened</em>

\dot V_{l} = \frac{k}{t_{l}} (Eq. 4)

\frac{\dot V_{l}}{k}  = \frac{1}{t_{l}}

By applying (Eqs. 3, 4) in (Eq. 2) and making some algebraic handling, we find that:

\frac{1}{t_{l}+3}+\frac{1}{t_{l}} = \frac{1}{2}

\frac{t_{l}+t_{l}+3}{t_{l}\cdot (t_{l}+3)} = \frac{1}{2}

2\cdot t_{l}+3 = t_{l}^{2}+3\cdot t_{l}

t_{l}^{2}-t_{l}-3 = 0 (Eq. 5)

Whose roots are determined by the Quadratic Formula:

t_{l,1}\approx 2.303\,h and t_{l,2} \approx -1.302\,h

Only the first roots offers a solution that is physically reasonable. Hence, the draining time when only the big drain is opened is 2.303 hours. And the time needed for the small drain is calculated by the following formula:

t_{s} = 2.303\,h+3\,h

t_{s} = 5.303\,h

The draining time when only the small drain is opened is 5.303 hours.

7 0
4 years ago
PLZZZZZZZZ HEALPPPPPP
Alborosie

Answer:

that looks hard but im thinking its 5-w

4 0
3 years ago
A dog is on a 20-foot leash in the backyard. Approximately how much area does the dog have to move around in the yard?
iragen [17]
With a 20 ft leash, the dog can move in the circle. Now, knowing that he can move around in a circle, we just need to use the circle formula. A = 3.14(r) squared.
Since you use 3.14 for pi; A = 3.14(20) squared --> A = 1256


Answer = 1256
3 0
3 years ago
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