Given that we have the change in temperature over 7 hours and we are looking for the change over 1 hour, we can divide the total change in temperature by 7. Thus, the change in temperature would be $\frac{42}{7} C^{\circ}$ .

Additionally, this can be solved by equations:

$\dfrac{42 \,\textrm{C}^{\circ}}{7 \,\textrm{hours}} = \dfrac{x \,\textrm{C}^{\circ}}{1 \,\textrm{hour}}$

$1 \,\textrm{hour} \cdot \dfrac{42 \,\textrm{C}^{\circ}}{7 \,\textrm{hours}} = x \,\textrm{C}^{\circ}$

$\dfrac{42}{7} \,\textrm{C}^{\circ} = x \,\textrm{C}^{\circ}$

$\dfrac{42}{7} = x$

By using two different methods, we can determine that the change each hour was equal to 42/7 C° per hour.

6 0

3 years ago

How to find the hypotenuse of a triangle?

ExtremeBDS [4]

To find the hypotenuse of the triangle
you use the length of the legs
Plug it into the Pythagorean Theorem

so $a^{2} + b^{2} = c^{2}$

$a^{2}$ is one of the legs

and

$b^{2}$ is the other leg

then

$c^{2}$ is the hypothenuse

5 0

3 years ago

If the given is DEFG is a kite how do I prove that triangle EFH is congruent to triangle GFH

nordsb [41]

Answer:

They both have H hoel

Step-by-step explanation:

4 0

2 years ago