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lozanna [386]
3 years ago
14

4xsquared-3xy+9ysquared-3 (5xy+7ysquared)

Mathematics
1 answer:
Flauer [41]3 years ago
7 0
4x² - 3xy + 9y² - 3(5xy + 7y²)
4x² - 3xy + 9y² - 3(5xy) - 3(7y²)
4x² - 3xy + 9y² - 15xy - 21y²
4x² - 3xy - 15xy + 9y² - 21y²
4x² - 18xy - 12y²
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Answer:

The correct option is b) 1.70

Step-by-step explanation:

Consider the provided information.

The weekly sulfur dioxide emissions follow a normal distribution with a mean of 1000 ppm (parts per million) and a standard deviation of 25.

Thus, μ=1000 and σ = 25

The CEO wants to know if the mean level of emissions is different from 1000.

Therefore the null and alternative hypothesis is:

H_0:\mu =1000 and H_a:\mu \neq1000

The sample size is n = 50 and \bar x=1006 ppm.

Now calculate the test statistic by using the formula: z=\frac{\bar x-\mu}{\frac{\sigma}{\sqrt{n}}}

Substitute the respective values in the above formula.

z=\frac{1006-1000}{\frac{25}{\sqrt{50}}}

z=\frac{6}{\frac{25}{\sqrt{50}}}=1.697\approx 1.70

Hence, the correct option is b) 1.70

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