See picture for steps and answer
We let y equal to the elevation above sea level so that the elevation of the rock climber after x minutes of climbing would be:
y = 2x + 50
His initial height can be calculated when x is equal to zero it is when the climber is not yet climbing. Therefore, the rock climber'sinitial height above sea level would be 50 meters.
Answer:
y = 3/5 x + 2.
Step-by-step explanation:
Use the point-slope equation of a straight line:
y - y1 = m (x - x1) where m = the slope amd (x1, y1) is a point on the line.
Here:
m = (5- (-1)) / (5 - (-5))
= 6/10
= 3/5.
Substituting for m and (5, 5):
y - 5 = 3/5(x - 5)
y - 5 = 3/5x - 3
y = 3/5 x + 2.
A line perpendicular to y = 2x - 1 must have the slope -1/2 (negative reciprocal of 2).
Thus, the eq'n of the new line is y+2 = (-1/2)(x+2).
