Polynomial of degree seven can have the maximum 7 real solutions,
so maximum number of x-intercepts is also 7.
Answer:
1. Slope: -3/4
2. Point-slope: y+4=-3/4(x+4)
3. Slope-intercept: y=-3/4x-7
4. Standard form: 3x+4y=-28
Step-by-step explanation:
1. To find the slope, use the slope formula, which is: y2-y1/x2-x1.
Plug the y-coordinates into the top part of the equation and the x-coordinates into the bottom part.
2--4/-4-4
2+4/-8 = 6/-8, or 3/-4
2. Use the slope and one of the x and y coordinates to put the equation into point-slope form. Recall that point-slope form is: y-y1=m(x-x1). Let's use the coordinates (4,-4).
y+4=-3/4(x+4)
3. To put the point-slope equation into slope-intercept form (y=mx+b), you need to distribute -3/4 to x+4 and subtract 4 from both sides.
When you distribute, the equation becomes:
y+4=-3/4x-3
Finally, when you subtract 4, the equation becomes:
y=-3/4x-7
4. Standard form is written as x+y= #.
To convert y=mx+b to standard form, first subtract -3/4x from both sides.
-3/4x + y = -7
Multiply everything by 4
3x + 4y = -28
Answer:
Step-by-step explanation:
Vertex form of a quadratic equation;
Vertex of the parabolas (h, k)
The vertex of the parabola is either the minimum or maximum of the parabola. The axis of symmetry goes through the x-coordinate of the vertex, hence h = -3. The minimum of the parabola is the y-coordinate of the vertex, so k= 7. Now substitute it into the formula;
Now substitute in the given point; ( -1, 9) and solve for a;
Hence the equation in vertex form is;
In standard form it is;
