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Ber [7]
3 years ago
7

Round 630 to the nearest ten

Mathematics
2 answers:
Sergio [31]3 years ago
8 0
Rounding it to the nearest tens place . . . here are your options:
 . . .
620
630
640
 . . .

obviously 630 rounds to 630 since it is equal to it

but the rule is, if the rounded value (in this case, the value in the ones place) is equal to or greater than five (5), then you round up . . . if the rounded value is less than five (5), then you round down . . . since our value in the ones place is 0 (which is less than 5), we round down to the next multiple of ten, which happens to be 630 itself.
rjkz [21]3 years ago
3 0
630 rounded to the nearest tenth is 600.4 and under let it rest 5 and up wake it it up
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What is the value of the 2 in 3.25?
gizmo_the_mogwai [7]
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4 years ago
Consider a single span of the spinner. Which events are mutually exclusive? Select two options. Landing on a shaded portion and
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Answer:

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Step-by-step explanation:

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3 years ago
Read 2 more answers
2. The sum of two integers is 74. The larger is 26 more than twice the smaller. Find the two integers.
kompoz [17]
74=x+y is the equation at the beginning we will say that x is the smaller number and y is the larger one. Now we substitute the larger number (y) for 26+2x. Plug that into the beginning equation to get 74= x+ 26+2x. Now solve.
74=3x+26
48=3x
16=x
So we know that our smaller number is 16. To find the larger number we plug the value of the smaller number into the equation for the larger number like this.
y=26+2x
y=26+2(16)
y=26+32
y=58.
So to check our answer we can plug in both values into the beginning equation.
74=58+16
74=74.
So to sum this up the smaller number is 16 and the larger number is 58.

4 0
3 years ago
Helppppppp no links or anything, please give the answer
Arlecino [84]

Answer:

Step-by-step explanation: the answer is x^2+10x+21

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