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3 years ago

Round 630 to the nearest ten

2 answers:

8 0

Rounding it to the nearest tens place . . . here are your options:
. . .
620
630
640
. . .

obviously 630 rounds to 630 since it is equal to it

but the rule is, if the rounded value (in this case, the value in the ones place) is equal to or greater than five (5), then you round up . . . if the rounded value is less than five (5), then you round down . . . since our value in the ones place is 0 (which is less than 5), we round down to the next multiple of ten, which happens to be 630 itself.

rjkz [21]3 years ago

3 0

630 rounded to the nearest tenth is 600.4 and under let it rest 5 and up wake it it up

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Answer:

The number of minutes advertisement should use is found.

x ≅ 12 mins

Step-by-step explanation:

(MISSING PART OF THE QUESTION: AVERAGE WAITING TIME = 2.5 MINUTES)

For such problems, we can use probability density function, in which probability is found out by taking integral of a function across an interval.

Probability Density Function is given by:

$f(t)=\left \{ {{0 ,\-t$

Consider the second function:

$f(t)=\frac{e^{-t/\mu}}{\mu}\\$

Where Average waiting time = μ = 2.5

The function f(t) becomes

$f(t)=0.4e^{-0.4t}$

The manager wants to give free hamburgers to only 1% of her costumers, which means that probability of a costumer getting a free hamburger is 0.01

The probability that a costumer has to wait for more than x minutes is:

$\int\limits^\infty_x {f(t)} \, dt= \int\limits^\infty_x {}0.4e^{-0.4t}dt$

which is equal to 0.01

Solve the equation for x

$\int\limits^{\infty}_x {0.4e^{-0.4t}} \, dt =0.01\\\\\frac{0.4e^{-0.4t}}{-0.4}=0.01\\\\-e^{-0.4t} |^\infty_x =0.01\\\\e^{-0.4x}=0.01$

Take natural log on both sides

$ln (e^{-0.4x})=ln(0.01)\\-0.4x=ln(0.01)\\-0.4x=-4.61\\x= 11.53$

<h3>Results</h3>

The costumer has to wait x = 11.53 mins ≅ 12 mins to get a free hamburger

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Calvin works at a facility which processes apples. It costs the facility $0. 68 to make either a jar of applesauce or a bottle o

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The number of bottles the facility requires to sell when it breaks is given by

a system of two simultaneous equations.

When the facility breaks even, it would have sold 7<u>7,579 bottles of apples juice</u>.

Reasons:

The cost to make a jar of applesauce or a bottle of apple juice = $0.68

Number of jars of applesauce to be sold foe every 2 bottles of apple juice = 3 jars

The selling price for a jar of applesauce = $2.20

Selling price for a bottle of apple juice = $3.15

Annual overhead cost excluding production cost = $368,500

Required: Number of bottles of apple juice sold by the facility when it breaks even annually.

Solution:

Let <em>J</em> represent the number of bottles of apple juice sold, and let <em>S</em> represent the number of jars of apple sauce, by excluding the production cost, we have;

(3.15 - 0.68)·J + (2.2 - 0.68)·S = 368,500

S : J = 3 : 2

Which gives;

$\displaystyle \frac{S}{J} = \mathbf{ \frac{3}{2}}$

$\displaystyle S= \frac{3}{2} \cdot J$

Therefore;

$\displaystyle (3.15 - 0.68) \cdot J + (2.2 - 0.68) \cdot S = (3.15 - 0.68) \cdot J + (2.2 - 0.68) \cdot \frac{3}{2} \cdot J = \mathbf{368,500}$

Which gives;

$\displaystyle (3.15 - 0.68) \cdot J + (2.2 - 0.68) \cdot \frac{3}{2} \cdot J = \mathbf{ \frac{19 \cdot J }{4} } = 368,500$

$\displaystyle J = \frac{368,500 \times 4}{19} = \frac{1474000}{19}=77578\frac{18}{19} \approx 77,579$

The number of bottles of apple juice sold, J ≈ <u>77,579 bottles</u>

Learn more about simultaneous equations here:

brainly.com/question/10724274

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