Answer:
x=8
base side of isosceles triangle
y=√{8²+8²}=8√2
Answer:
3(2x^2-3x+14)
Step-by-step explanation:
6x^2-9x+42
All three terms have a common factor of 3
3(2x^2-3x+14)
Now let's focus on 2x^2-3x+14 and bring down the factor 3 later
so a=2
b=-3
c=14
Let's try to find two factors for ac that multiply to be a*c and add up to be b.
ac=28
b=-3
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ac=7(4)=14(2)=8(2)
Even if I made these pairs with both negatives nothing would give me -3
So you can only go as far as 3(2x^2-3x+14)
Here is another thing to help you if you have ax^2+bx+c and b^2-4ac<0 then it can't be factored (over reals)
Answer:
y=sec(x) + 1
Step-by-step explanation:
The Sec(x) = 1/Cos(x) which has a minimum of +1 when positive, and -1 when negative. Adding +1 to it gives a range of (-∞,0) and when negative (2,∞)
