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Anna [14]
3 years ago
12

Does anyone know the answer to the question below.

Mathematics
1 answer:
Troyanec [42]3 years ago
5 0

Answer:

jdbvdnxndndndnbfgfhdntvdjkfvrjfjrjtofj

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Which of the equations below could be the equation of this parabola?
GREYUIT [131]

D⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

4 0
3 years ago
Read 2 more answers
Mrs. Bonse bought a box of erasers. The box had 5 different shapes of erasers. There were 8 of each shape of eraser in the box.
JulsSmile [24]

Answer:

Gail is correct and Brianne is incorrect.

Step-by-step explanation:

If there are 5 different shaped erasers and 8 of each, you would have to multiply 5x8 which equals 40. If there are 4 people in the group, 40 divided by 10 equals 4.

4 0
3 years ago
9-3÷1/3+1 <br> can you pleas solve this question <br> please hurry
Alex787 [66]

Answer:

9

Step-by-step explanation:

pemdas

9-3÷1/3+1

division

3 and 1/3 becomes 1

we have 9-1+1

which simplifies to 9

4 0
3 years ago
Suppose the number of insect fragments in a chocolate bar follows a Poisson process with the expected number of fragments in a 2
leonid [27]

Answer:

a)The expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55

b)0.6004

c)19.607

Step-by-step explanation:

Let X denotes the number of fragments in 200 gm chocolate bar with expected number of fragments 10.2

X ~ Poisson(A) where \lambda = \frac{10.2}{200} = 0.051

a)We are supposed to find the expected number of insect fragments in 1/4 of a 200-gram chocolate bar

\frac{1}{4} \times 200 = 50

50 grams of bar contains expected fragments = \lambda x = 0.051 \times 50=2.55

So, the expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55

b) Now we are supposed to find the probability that you have to eat more than 10 grams of chocolate bar before ending your first fragment

Let X denotes the number of grams to be eaten before another fragment is detected.

P(X>10)= e^{-\lambda \times x}= e^{-0.051 \times 10}= e^{-0.51}=0.6004

c)The expected number of grams to be eaten before encountering the first fragments :

E(X)=\frac{1}{\lambda}=\frac{1}{0.051}=19.607 grams

7 0
3 years ago
Can someone help me plzzzz!
oksian1 [2.3K]

8.2is the answer

Step-by-step explanation:

|CB|+8

7 0
3 years ago
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