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3 years ago

Can someone clearly explain and workout Q19? Much appreciated

Mathematics

1 answer:

Anna007 [38]3 years ago

5 0

The x coefficient is 2
Take half of 2 to get 2/2 = 1
Square 1 to get 1^2 = 1

Add and subtract 1 to the expression. This is the same as adding 0.

x^2 + 2x + 2
x^2 + 2x + 2 + 0
x^2 + 2x + 2 + (1-1)
(x^2 + 2x + 1) + 2 - 1
(x+1)^2 + 1

Answer: (x+1)^2 + 1

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In a room, there are 450 students of which 20% are girls. A group of students have mobile phones with them, of which 40% are gir

andrew-mc [135]

Answer:

216 boys

Step-by-step explanation:

450 students: 20% girls, 80% boys

450*20%=90 girls

450*80%=360 boys

Students having mobile phones: 40% (OF THE 90) girls, 60% (OF THE 360) boys

90*40%=36 girls

360*60%=216 boys

[We honestly don't need to care about the girls without mobile phones as they are only asking how many boys have mobile phones]

4 0

3 years ago

Read 2 more answers

Write the equation of a line perpendicular to y=0.25x-7 and passes through the point -6,8

horrorfan [7]

the equation of a line perpendicular to $y=0.25x-7$ and passes through the point (-6,8) is $y=-4x+30$

Step-by-step explanation:

We need to write equation of line perpendicular to $y=0.25x-7$ and passes through the point (-6,8)

Since the line $y=0.25x-7$ is in slope-inetercept form $y=mx+b$

the slope of line m = 0.25

As, the new line is perpendicular to the given line so, slopes of lines that are perpendicular are: slope = -1/slope1

So, slope will be -1/0.25 = -4

Now, finding y-intercept.

$y=mx+b8=4(-6)+b\\8=-24+b\\b=8+24\\b=30$

So, value of y-intercept b = 30

Now the equation of the required line having slope m= -4 and b =30 will be:

$y=mx+b\\y=-4x+30$

So, the equation of a line perpendicular to $y=0.25x-7$ and passes through the point (-6,8) is $y=-4x+30$

Keywords: Equation of line, slope-intercept form

Learn more about slope-intercept form at:

#learnwithBrainly

3 0

3 years ago

20. What is the y-intercept of the line<br> y + 11 = -2(x + 1.5).

Vinvika [58]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Quadratics need help making parabola

timama [110]

Answer:

The equation of the parabola is $y = \frac{1}{3}\cdot x^{2}-\frac{4}{3}\cdot x -4$ , whose real vertex is $(x,y) = (2, -5.333)$ , not $(x,y) = (2, -5)$ .

Step-by-step explanation:

A parabola is a second order polynomial. By Fundamental Theorem of Algebra we know that a second order polynomial can be formed when three distinct points are known. From statement we have the following information:

$(x_{1}, y_{1}) = (-2, 0)$ , $(x_{2}, y_{2}) = (6, 0)$ , $(x_{3}, y_{3}) = (0, -4)$

From definition of second order polynomial and the three points described above, we have the following system of linear equations:

$4\cdot a -2\cdot b + c = 0$ (1)

$36\cdot a + 6\cdot b + c = 0$ (2)

$c = -4$ (3)

The solution of this system is: $a = \frac{1}{3}$ , $b = - \frac{4}{3}$ , $c = -4$ . Hence, the equation of the parabola is $y = \frac{1}{3}\cdot x^{2}-\frac{4}{3}\cdot x -4$ . Lastly, we must check if $(x,y) = (2, -5)$ belongs to the function. If we know that $x = 2$ , then the value of $y$ is: