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zhuklara [117]
3 years ago
9

Can someone clearly explain and workout Q19? Much appreciated

Mathematics
1 answer:
Anna007 [38]3 years ago
5 0
The x coefficient is 2
Take half of 2 to get 2/2 = 1
Square 1 to get 1^2 = 1

Add and subtract 1 to the expression. This is the same as adding 0. 

x^2 + 2x + 2
x^2 + 2x + 2 + 0
x^2 + 2x + 2 + (1-1)
(x^2 + 2x + 1) + 2 - 1
(x+1)^2 + 1

Answer: (x+1)^2 + 1

 
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In a class test (+ 5) marks are given for every correct answer and (-3) marks are given for every incorrect answer.
OLEGan [10]

Answer:

a. 4 marks b. 9 questions

Step-by-step explanation:

a) Anu gets 8 correct answer and 12 incorrect answers what is her score?

Since Anu got 8 correct answer and 12 incorrect answers, and + 5 marks is given for every correct answer and (-3) marks are given for every incorrect answer, the total score for correct answers is number of correct answer × marks for correct answer = 8 × (+ 5) = 40.

Also,  the total score for incorrect answers is number of incorrect answer × marks for incorrect answer = 12 × (- 3) = -36.

Anu's total score = total score for correct answers + total score for incorrect answers = 40 + (-36) = 40 - 36 = 4 marks.

So, Anu scored 4 marks.

b) Sam answered all the questions and scored 28 marks though he got 11 correct answers.  How many incorrect answers had he attempted?

Let x be the number of incorrect answers. Since the marks for incorrect answers is -3, then his total score for incorrect answers is -3x.

Since Sam got 11 correct answers and is given + 5 marks for each correct answer, then his total score for correct answers is 11 × (+5) = +55.

Since he gets a total of 28 marks, we have that total score for incorrect answer + total score for correct answer = 28.

So, -3x + 55 = 28

Solving for x, we have

-3x = 28 - 55

-3x = -27

x = -27/-3

x = 9

Since x = 9, Sam attempted 9 incorrect questions.

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6 0
3 years ago
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17.3 is ten times as much as 1.73.
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1242 is your answer.

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Explanation:

The first step is to figure out what the equation is. When unconventional math symbols are used, and when there are no grouping symbols identifying operands, that can be the most difficult step. Here, we think the equation is supposed to be ...

  \sqrt[3]{x+1}-2=0

It usually works well in radical equations to isolate the radical. Here that would mean adding 2 to both sides of the equation, to undo the subtraction of 2.

  \sqrt[3]{x+1}=2

Now, it is convenient to raise both sides of the equation to the 3rd power.

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  x=7

The equation is solved. The solution is x = 7.

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3 years ago
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