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3 years ago

5

What is the answer?????

1 answer:

irina [24]3 years ago

5 0

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Question 1<br> What is the solution of n² - 49 = 0?<br> 0 +7<br> 07<br> -7<br> O no solution

Sphinxa [80]

Hey there!

This can be written as $n^{2}-(7)^{2}$

This is in form of $\fbox{a^{2}-b^{2}}$ , it can be expanded as $\fbox{(a-b)(a+b)}$

=> (n-7)(n+7)=0
=> n -7 = 0 or n + 7 = 0
=> n = 7 or n = -7

So option 7 , -7 are correct.

Hope this is clear :)
Have a good day:)

7 0

1 year ago

Read 2 more answers

WILL GIVE BRAINLET<br><br> 5/6 + 7 1/3

Tems11 [23]

Answer:

It would be 8 1/6 im 90% sure

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

3 Express the following fractions in a different way:<br>(a) 1/4 = ? (b) 2/4 = ? (C) 1/2 = ?

lawyer [7]

Answer:

Step-by-step explanation:

A. 1.4. B. 2.4. C. 1.2

8 0

3 years ago

Find x. Leave answers in simplified radical form. (Step by step)

just olya [345]

Answer:

$\sf x = 4\sqrt{2}$

Given:

adjacent: 4 cm
hypotenuse: x cm
angle: 45°

<u>using cosine rule:</u>

$\sf cos(x) = \dfrac{adjacent}{hypotenuse}$

$\sf cos(45) = \dfrac{4}{x}$

$\sf x = \dfrac{4}{cos(45)}$

$\sf x = 4\sqrt{2}$

4 0

2 years ago

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I have the question in a screengrab. Thank you, whoever helps me.

nata0808 [166]

To simplify

$\sqrt[4]{\dfrac{24x^6y}{128x^4y^5}}$

we need to use the fact that

$\sqrt[4]{x^4}=|x|$

Why the absolute value? It's because $(-x)^4=(-1)^4x^4=x^4$ .

We start by rewriting as

$\sqrt[4]{\dfrac{2^23x^6y}{2^6x^4y^5}}$

$\sqrt[4]{\dfrac{2^23x^4x^2y}{2^42^2x^4y^4y}}$

Since $x\neq0$ , we have $\dfrac xx=1$ , and the above reduces to

$\sqrt[4]{\dfrac{3x^2y}{2^4y^4y}}$

Then we pull out any 4th powers under the radical, and simplify everything we can:

$\dfrac1{\sqrt[4]{2^4y^4}}\sqrt[4]{\dfrac{3x^2y}{y}}$

$\dfrac1{|2y|}\sqrt[4]{3x^2}$

where $y>0$ allows us to write $\dfrac yy=1$ , and this also means that $|y|=y$ . So we end up with

$\dfrac{\sqrt[4]{3x^2}}{2y}$

making the last option the correct answer.

7 0

2 years ago