Ask question

Ask question

All categories

3 years ago

10

A line with a slope of 10 passes through the points ( -5, - 9) and ( - 4,a). What is the value of a?

1 answer:

Setler79 [48]3 years ago

4 0

The slope is 10
(-5,-9)
(-4,-a)
a=-19
Because the slope is 10, that means when the input increases, the output will increases 10.

You might be interested in

Which algebraic expression is equivalent to the expression below? 4(5 + 8r) + 19

mr_godi [17]

Answer:

32r + 39

Step-by-step explanation:

<u>Step 1: Distribute</u>

4(5 + 8r) + 19

<em>20 + 32r + 19</em>

<em />

<u>Step 2: Combine like terms</u>

<em>32r + 39</em>

<em />

Answer: 32r + 39

7 0

3 years ago

Read 2 more answers

**22 POINTS** Please solve this fraction as a difference

Ghella [55]

Answer:

$\dfrac{x}{4}-\dfrac{7}{12}$

Step-by-step explanation:

The fraction is the equivalent of ...

$\dfrac{1}{12}{(3x-7)$

and the distributive property applies.

$=\dfrac{1}{12}(3x)-\dfrac{1}{12}(7)\\\\=\dfrac{3\cdot x}{3\cdot 4}-\dfrac{7}{12}\\\\=\dfrac{x}{4}-\dfrac{7}{12}$

3 0

3 years ago

The students in chemistry class have 75 milliliters of a pure acid which must be diluted to a solution that is 10% acid. How man

lana66690 [7]

Answer:

Add W ml

75*100 + W*0 = (75+W)*10

6 0

3 years ago

Henry ate 3/8 of a sandwich. Keith ate 4/8 of the same sandwich. How much more of the sandwich did Keith eat than Henry?

ludmilkaskok [199]

4/8-3/8=1/8more

Therefore Keith at 1/8 more of the sandwich than Henry.

6 0

2 years ago

A simple random sample of items resulted in a sample mean of . The population standard deviation is . a. Compute the confidence

Varvara68 [4.7K]

Answer:

(a): The 95% confidence interval is (46.4, 53.6)

(b): The 95% confidence interval is (47.9, 52.1)

(c): Larger sample gives a smaller margin of error.

Step-by-step explanation:

Given

$n = 30$ -- sample size

$\bar x = 50$ -- sample mean

$\sigma = 10$ --- sample standard deviation

Solving (a): The confidence interval of the population mean

Calculate the standard error

$\sigma_x = \frac{\sigma}{\sqrt n}$

$\sigma_x = \frac{10}{\sqrt {30}}$

$\sigma_x = \frac{10}{5.478}$

$\sigma_x = 1.825$

The 95% confidence interval for the z value is:

$z = 1.960$

Calculate margin of error (E)

$E = z * \sigma_x$

$E = 1.960 * 1.825$

$E = 3.577$

The confidence bound is:

$Lower = \bar x - E$

$Lower = 50 - 3.577$

$Lower = 46.423$

$Lower = 46.4$ --- approximated

$Upper = \bar x + E$

$Upper = 50 + 3.577$

$Upper = 53.577$

$Upper = 53.6$ --- approximated

<em>So, the 95% confidence interval is (46.4, 53.6)</em>

Solving (b): The confidence interval of the population mean if mean = 90

First, calculate the standard error of the mean

$\sigma_x = \frac{\sigma}{\sqrt n}$

$\sigma_x = \frac{10}{\sqrt {90}}$

$\sigma_x = \frac{10}{9.49}$

$\sigma_x = 1.054$

The 95% confidence interval for the z value is:

$z = 1.960$

Calculate margin of error (E)

$E = z * \sigma_x$

$E = 1.960 * 1.054$

$E = 2.06584$

The confidence bound is:

$Lower = \bar x - E$

$Lower = 50 - 2.06584$

$Lower = 47.93416$

$Lower = 47.9$ --- approximated

$Upper = \bar x + E$

$Upper = 50 + 2.06584$

$Upper = 52.06584$

$Upper = 52.1$ --- approximated

<em>So, the 95% confidence interval is (47.9, 52.1)</em>

Solving (c): Effect of larger sample size on margin of error

In (a), we have:

$n = 30$ $E = 3.577$

In (b), we have:

$n = 90$ $E = 2.06584$

<em>Notice that the margin of error decreases when the sample size increases.</em>

4 0

3 years ago