What is the elapsed time between 3:40 AM and 2 PM?

1 answer:

5 0

<span>10 hrs 20 mins just count and when you get to 12, go back to 1 but make sure you change it to either PM or AM</span><span />

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Suppose yoko borrows $3500 at an interest rate of 4% compounded each year Find the amount owed at the end of 1 year

olchik [2.2K]

Amount owed at the end of 1 year is 3640

<h3><u>Solution:</u></h3>

Given that yoko borrows $3500.

Rate of interest charged is 4% compounded each year

Need to determine amount owed at the end of 1 year.

In our case :

Borrowed Amount that is principal P = $3500

Rate of interest r = 4%

Duration = 1 year and as it is compounded yearly, number of times interest calculated in 1 year n = 1

<em><u>Formula for Amount of compounded yearly is as follows:</u></em>

$A=p\left(1+\frac{r}{100}\right)^{n}$

Where "p" is the principal

"r" is the rate of interest

"n" is the number of years

Substituting the values in above formula we get

$\mathrm{A}=3500\left(1+\frac{4}{100}\right)^{1}$

$\begin{array}{l}{A=\frac{3500 \times 104}{100}} \\\\ {A=35 \times 104} \\\\ {A=3640}\end{array}$

Hence amount owed at the end of 1 year is 3640

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2 years ago

Look at this set of ordered pairs:

forsale [732]

Answer: Yes

If I remember correctly, I believe these ordered pairs indicate a function, as there is exactly 1 output for every input (i.e., (output, input)). If there were 2 inputs of the same number, that'd make this relation not a function.

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2 years ago

URGENT MATH HELP BRAINLIEST

Lelechka [254]

Answer:

Step-by-step explanation:

a. This is a right triangle with two sides and one angle given.

-We apply Sine Rule to find the angle B:

$\frac{a}{Sin \ A}=\frac{b}{Sin \ B}=\frac{b}{Sin \ C}$

-The sides given are 10and 17 and the right angle 90°

$\frac{17}{Sin \ 90 \textdegree}=\frac{10}{Sin \ m\angle B}\\\\m\angle B=Sin^{-1}\frac{10}{(17/Sin \ 90\textdegree)}\\\\=36.03\textdegree$

Hence the angle B is 36.03°

b.We again use the sine rule to obtain the unknown angle w:

-15 corresponds to 90° and 9 corresponds to w°

$\frac{a}{Sin \ a}=\frac{b}{Sin \ B}\\\\\frac{15}{Sin \ 90\textdegree}=\frac{9}{Sin \ w\textdegree}\\\\\\\\w=Sin^{-1}(\frac{9}{15}), \ \ Sin \ 90\textdegree=1\\\\=36.87\textdegree$