<h3>Answer: Choice C. </h3><h3>Division[ (4x^3+2x^2+3x+5)^2, x^2+3x+1]</h3>
=============================================================
Explanation:
It honestly depends on the CAS program, but for GeoGebra for instance, the general format would be Division[P, Q]
Where,
- P = numerator = (4x^3+2x^2+3x+5)^2
- Q = denominator = x^2+3x+1
As another example, let's say we want to divide x^2+5x+6 all over x^3+7 as one big fraction
We would type in Division[x^2+5x+6, x^3+7]
Answer:
0.0006726759 to be exact.
Answer:
x = 5.5
Step-by-step explanation:
PM = MR
4x - 12 = -2x + 21 {add 2x to both the sides}
4x - 12 + 2x = -2x + 2x + 21
6x - 12 = 21 {Add 12 to both sides}
6x - 12 + 12 = 21 + 12
6x = 33
x = 33/6
x = 5.5
Answer:
4,5,6 are the three consecutive numbers. 16, 25 and 36 are their squares.
Step-by-step explanation:
Let the three consecutive numbers be x, (x+1), (x+2)
Now, the squares of these three numbers are 
Sum = 77
∴by the problem ,

{Taking 3 common }

{By factorization}

Therfore,

<em>X can't be negetive </em>
∴ 
The squares of the three consecutive numbers are 16, 25, 36
The three consecutive numbers whose sum is 77 are 4, 5, 6
Answer: 12cm
Step-by-step explanation: