We are asked to solve for the value of "x" such that when it is added in the original area of the park it will double the area. Let us compute first the area of the original dog park (A1) and the solution is shown below:
Area = Lenght*Width = L*W where L=30 yards and W=20 yards
Area = 30*20
Area = 600 yards squared
Solving for the x, when x is added to both sides which double the area:
A1*2 = (L + 2x)*W
600*2 = (30+2x)*20
1200 / 20 = 30+2x
60 = 30 + 2x
60-30 = 2x
30/2 =x
15 = x
The value of x is 15 yards.
Answer:
f(0) = g(0)
Step-by-step explanations
if a function h(x) passes through [a,b] then it can be said that h(a)=b.
given that, g(x) passes through (-2,0) and (0,4)
so, g(-2)=0, g(0)=4.
f(x) passes through (0,4) and (2,0)
so, f(2)=0, f(0)=4.
therefore, f(0)=g(0)=4.
so, first option is correct.
<span>7.25 = 7 and 25/100 = 7 and 1/4</span>
2х3+10х+2у2-х-у=2х3+9х+2у2-у=2*3in3+9*3+2*5in2-5=2*27+27+2*25-5=54+27+50-5=126
Answer:
1
Step-by-step explanation:
x-7=-5x-1
x-(-5x)-7=-1
x+5x-7=-1
6x-7=-1
6x=-1+7
6x=6
x=6/6
x=1
