Answer:
BC < ED ⇒ answer A
Step-by-step explanation:
* Lets revise some facts in the triangle
- If one side of a triangle is longer than another side, then the angle
opposite the longer side will be larger than the angle opposite the
shorter side
- If one angle in a triangle is larger than another angle in a triangle,
then the side opposite the larger angle will be longer than the side
opposite the smaller angle
* Lets solve the problem
- In the two triangles BCD and DEB
∵ CD = 8 and BE = 8
∴ CD = BE
∵ Side BD is a common side in the two triangles
- The third side in Δ BCD is BC and the third side in DEB is DE
∵ BC is the opposite side to the angle of measure 24°
∵ ED is the opposite side to the angle of measure 30°
∵ The measure 24° < the measure 30°
∴ The side opposite to the angle of measure 24° < the side opposite
to the angle of measure 30°
∵ The other two sides of the 2 triangles BCD and DEB are equal
∴ We can compare between the 3rd sides in the Δ BCD and Δ DEB
∴ BC < ED
Answer:
1.
-2 = x/4 + 1
Subtract 1 from both sides:
-2 - 1 = x/4 + 1 - 1
-3 = x/4
Multiply both sides by 4:
-3 * 4 = x/4 * 4
-12 = x
2.
3x+5
3.
X= 12 or 18
This could be read two different ways.
0=2/3x-12
12=2/3x
12÷2/3=x
12*3/2=x
18=x
—-OR—-
0=2/3(x-12)
0=2/3x-8
8=2/3x
8÷2/3=x
8*3/2=x
12=x
2.40 before a 30% discount is 0.72
Answer:
The answer to your question is: the first option - 9/ 
Step-by-step explanation:
Process
cosФ = adjacent side / hypotenuse
-1/9 = adjacent side / hypotenuse
adjacent side = -1 hypotenuse = 9
c² = a² + b²
b² = c² - a²
b² = 81 - 1
b =
b = opposite side
But b is negative because we are in the third quadrant.
b = -
Finally csc Ф = hypotenuse / opposite side
csc Ф = - 9 / 
Answer:
161 correo o no ............