If f(x) = 3x to the 2nd+ 1 and g(x) = 1-x, what is the value of (f-g)(2)?

1 answer:

3 0

$\displaystyle\\f(x)=3x^2+1\\g(x)=1-x\\\\(f-g)(x)=f(x)-g(x)=3x^2+1-(1-x)=3x^2+1-1+x=\boxed{3x^2+x}\\\\(f-g)(2)=f(2)-g(2)=3\cdot2^2+2=3\cdot4+2=12+2=\boxed{14}$

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