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Ghella [55]
3 years ago
9

Two vertices of a polygon are ( 7, -18) and (7, 18). What is the length of this side of the polygon?

Mathematics
1 answer:
Scilla [17]3 years ago
8 0
Because the two vertices have the same x-coordinate, the side is a vertical line. It starts vertically from -18 to 18

the length = 18 - (-18)
the length = 18 + 18
the length = 36

The length of the side is 36 unit
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In 1992​, there were 41 comma 984 shopping centers in a certain country. In 2002​, there were 48 comma 225. ​(a) Write an equati
Illusion [34]

Answer:

Step-by-step explanation:

The equation expressing the number y of shopping centers in terms of the number x of years after 1992 will be LINEAR in nature

The standard equation is expressed as;

y = mx+c

m is the slope

c is the intercept

If in 1992​, there were 41,984 shopping centers in a certain country and in 2002​, there were 48,225 we can express this as coordinate points

(0, 41984) and (10, 48,225)

Get the slope

m = 48,225-41,984/10-0

m = 6241/10

m = 624.1

Get the intercept, substitute m = 624.1 and the point (0,48225) into the formula y = mx+c

48225 = 624.1(0)+c

48225 = 0+c

c = 48225

Get the required equation

y = 624.1x+48225

5 0
3 years ago
Will give brainliest answer
garri49 [273]

Answer:

Step-by-step explanation:

Diameter is 7cm

radius is diameter/2 = 7cm/2 = 3.5cm

7 0
4 years ago
Read 2 more answers
WILL MARK BRAINLIEST!!! Given p(x)=x3−4x2+15x+k and the remainder of the division of p(x) by (x+1) is equal to −8, what is the r
balandron [24]
Use the polynomial remainder theorem. If p(x) is a polynomial of degree n>1, then we can divide by a linear term x-c to get a quotient q(x) and remainder r(x) of the form

\dfrac{p(x)}{x-c}=q(x)+\dfrac{r(x)}{x-c}\iff p(x)=(x-c)q(x)+r(x)

Then when x=c, we get p(c)=r(c). In other words, the value of p(x) at x=c tells you the value of the remainder upon dividing p(x) by x-c.

So given that p(x)=x^3-4x^2+15x+k, and the remainder upon dividing p(x) by x+1 is -8, we know that r(-1)=-8, so

\dfrac{x^3-4x^2+15x+k}{x+1}=q(x)-\dfrac8{x+1}
\dfrac{x^3-4x^2+15x+k+8}{x+1}=q(x)

Since q(x) is a polynomial (not a rational expression), then we know that x+1 divides x^3-4x^2+15x+k+8 exactly. In particular, the remainder term of this quotient is 0. We can use long or synthetic division to determine q(x). I prefer typing out the work for synthetic division:

-1   |   1   -4   15    k + 8
.     |        -1     5       -20
- - - - - - - - - - - - - - - - - -
.     |   1   -5    20    k - 12

The remainder here has to be 0, so k-12=0\implies k=12.

Finally, we can get the remainder upon dividing p(x) by x-1 by evaluating p(1), which gives p(1)=24.
6 0
3 years ago
Read 2 more answers
Name that Circle Part!
andriy [413]

Answer:

Good luck

Step-by-step explanation:

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3 years ago
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stepladder [879]
Answer below hope it helped

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