Answer:
Step-by-step explanation:
Here's the game plan. In order to find a point on the x-axis that makes AC = BC, we need to find the midpoint of AB and the slope of AB. From there, we can find the equation of the line that is perpendicular to AB so we can then fit a 0 in for y and solve for x. This final coordinate will be the answer you're looking for. First and foremost, the midpoint of AB:
and
Now for the slope of AB:
and
So if the slope of AB is 1/3, then the slope of a line perpendicular to that line is -3. What we are finding now is the equation of the line perpendicular to AB and going through (0, 3):
and filling in:
y - 3 = -3(x - 0) and
y - 3 = -3x + 0 and
y - 3 = -3x so
y = -3x + 3. Filling in a 0 for y will give us the coordinate we want for the x-intercept (the point where this line goes through the x-axis):
0 = -3x + 3 and
-3 = -3x so
x = 1
The coordinate on the x-axis such that AC = BC is (1, 0)
Answer:
slope-intercept form: y = x+2
The slope is 1
y-interspet is -2
Step-by-step explanation:
hope it helps
。☆✼★ ━━━━━━━━━━━━━━ ☾ ━━━━━━━━━━━━━━ ★✼☆。
- The equation :
Area = length x width
- Substitute the values in :
Area = (x - 5)(x - 5 + 22)
(Note : the 'x' is for the algebraic expression x in the example above)
- Now you have to simplify the second parenthesis:
Area = (x - 5)(x + 17)
- Now expand :
Area = x^2 + 17x - 5x - 85
- Simplify by collecting like terms :
Area = x^2 + 12x - 85
(Note : x^2 means x squared)
Now you have your answer as:
x^2 + 12x - 85 feet^2
Have A Nice Day ❤
Stay Brainly! ヅ
- Ally ✧
。☆✼★ ━━━━━━━━━━━━━━ ☾ ━━━━━━━━━━━━━━ ★✼☆。
A relation is (also) a function if every input x is mapped to a unique output y.
In terms of graphical representation, this implies that a graph represents a function if there doesn't exist a vertical line that intersects the graph more than once. So:
- The first graph is exactly a vertical line, so it's not a function.
- The second graph represents the function y=x, so it's a function: you can see that every possible vertical line crosses the graph only once.
- The third graph is not a function, because you can draw vertical lines that cross the graph twice.
- Similarly, in the fourth graph you can draw vertical lines that cross the graph twice
- The fifth graph is a function, because every vertical line crosses the graph once
- The last graph is a function, although discontinuous, for the same reason.