Answer:
11, 60, 61 and 12, 35, 37
Step-by-step explanation:
Using trigonometry (SOHCAHTOA), <WZX is our main angle that we will be using. Our H or hypotenuse is the ZX or 7 because it is longest side in the triangle XZW, the A or adjacent is ZW or X. Then you set up your equation using the CAH of SOHCAHTOA and solve. To find WX, you use the same H or hypotenuse is the ZX or 7 because it is longest side in the triangle XZW and the O or opposite is WX which is your X. For setting up your equation you use the SOH of SOHCAHTOA and solve. You then double each of your measurements you got for ZW and WX and add them together to get your perimeter. Good luck! Let me know if you still need help!
For this problem, we will take the given information and use it to create an expression representing the problem. We want the expression to equal the amount Dylan has.
Let's start by defining a variable.
d=dollars Leo has
We know that Dylan has 3 more dollars than twice the amount Leo has. We can take this information and create our expression.
2d+3 is our expression.
We multiply our variable by 2 and then add 3 since Dylan has twice the amount Leo has plus an addition of 3 more dollars.
Therefore, the solution is 2d+3.
Since you want to use the SAS theorem, you must find sides that are either side of angles BAC and DAE. You have already made use of sides AE and AC, so the other sides you need to choose are AB and AD. The appropriate relationship for similarity is ...
... AD = 2AB
since you want the sides of triangle ADE to be twice then length of those in triangle ABC.
Answer:
- 6 2/3 qt 80%
- 13 1/3 qt 20%
Step-by-step explanation:
It is often convenient to solve a mixture problem by letting a variable represent the quantity of the higher-concentration contributor to the mix.
__
We can let x represent the number of quarts of 80% solution needed. Then (20-x) is the number of quarts of 20% solution needed. The amount of salt in the final mix is ...
0.80x +0.20(20-x) = 0.40(20)
0.60x = 0.20(20) . . . . . . . . subtract 0.20(20) and simplify
x = 20/3 = 6 2/3 . . . . . . . . . divide by 0.60; quarts of 80% solution
(20 -x) = 13 1/3 . . . . . . . . . . amount of 20% solution needed
The teacher should mix 6 2/3 quarts of 80% solution with 13 1/3 quarts of 20% solution.
