All categories

3 years ago

Ten thousand more than 300,000+90,000+5000+40

Mathematics

1 answer:

mina [271]3 years ago

6 0

300,000+90,000+5,000+40=395,040
395,040+10000=405,040

You might be interested in

4. Which property of operations is used to write 15x + 9 as 9 + 15x?

suter [353]

Solution: The commutative property of addition states that when two numbers are being added, their order can be changed without affecting the sum.

8 0

3 years ago

Complete the table <br> y=1/4x-2

igomit [66]

Answer:

-4, -3, -2, -1, 0

Step-by-step:

1st: 1/4(-8) - 2 = -4 = y

2nd: 1/4(-4) - 2 = -3 = y

3rd: 1/4(0) - 2 = -2 = y

4th: 1/4(4) - 2 = -1 = y

5th: 1/4(8) - 2 = 0 = y

4 0

3 years ago

Read 2 more answers

HELP HELP PLEASE!! D:<br> Determine the missing side length!! <br> PLEASE NO CAP!!

charle [14.2K]

Answer:

missing side length = 9

Step-by-step explanation:

$c^{2} = a^{2} + b^{2}$

a = 6

b = 7

c = missing side

$c^{2} = 6^{2} + 7^{2}$

$c^{2} = 36 + 49$

$c^{2} = 85$

$\sqrt{c^{2} } = \sqrt{85}$

$c = 9.219 = 9$

5 0

3 years ago

the mgf of a random variable x is e^3(e^t-1). Find P[mean - standard deviation squared < X < 1/2( mean + standard deviatio

postnew [5]

The given MGF is that for a random variable following a Poisson distribution with parameter $\lambda=3$ .

This means $\mathbb E(X)=\mathbb V(X)=\lambda$ , and $X$ has PMF

$f_X(x)=\begin{cases}\dfrac{3^xe^{-3}}{x!}&\text{for }x\ge0\\0&\text{otherwise}\end{cases}$

So, the desired probability is

$\mathbb P\left(\lambda-\lambda^2$

This is equivalent to

$\displaystyle\sum_{x=0}^2\mathbb P(X=x)=\sum_{x=0}^2\frac{3^x}{x!e^3}=\frac{17}{2e^3}\approx0.4232$

8 0

4 years ago

The table shows the total cost of different numbers of tickets decided whether it makes sense to use a constant rate to describe

GalinKa [24]

34.50/6 = 5.75

44/8 = 5.5

52.5/10 = 5.25

As the number of tickets increase, the cost per ticket decreases.

So it does not make sense to use a constant rate.

5 0

1 year ago

Read 2 more answers