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djverab [1.8K]
3 years ago
10

Help with this question please also explain how you got your answer. Will mark brainliest.

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
3 0
Green.


You first must find the Least Common Denominator(LCD) of the fractions. You find that it is 20. 4/5 will turn into 16/20 because you must make it have a denominator with 20, and by doing so, you must multiply to get 20. 4×4=16, 5×4=20: 16/20. For 1/2, simply multiply by 10 to get 20 as the denominator. 1×10=10, 2×10=20: 10/20. Compare the two. You may convert the fractions to decimals to make your answer reasonable. 16/20 is clearly more than 10/20, so there is your answer.

P.S

16/20 is 0.8 as a decimal.
10/20 is 0.5 as a decimal.

Oh, and You're welcome!
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At which of the given values is the graph discontinuous?
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Step-by-step explanation:

You can solve the problem shown above keeping on mind the facts shown below:

Observe that there is a point in the graph in which there is a jump or a discontinuity between both parts of the function.

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A quadratic polynomial with real coefficients and leading coefficient is called if the equation is satisfied by exactly three re
lukranit [14]

p(1) = 1

Let p(x) = x2 + bx = c

then, p(p(x)) = (x2 + bx + c)² + b(x2 + bx + c) + c

Sum of roots of p(p(x)) is given by = - (coefficient of x3/constant term)

= -2b/c2+bc+c = f(a,b) (say)

For critical points,

∂f/∂c = 0 and ∂f/∂b = 0

= 2b(2c+b+1)/c2+bc+c = 0 and - {( c2+bc+c)²- 2b (c)/ ( c2+bc+c)²}= 0

= b(2c+b+1) =0  

= b= 0 or b= - (1+2c)  = -(2c(c+1))/c2+bc+c = 0

If c=0 , b= -1  => c= 0 or c=-1

If c = -1 ,b = 1

thus we have the following possibility for (b,c)

(0,0) , (0,-1) , (-1,0) ,(1,-1).

At (0,0) f(0,0) = not defined

(0,-1) f(0,-1) = 0

(1,-1) f(1,-1) = 2

(-1,0) is not possible.

p(x) = (x2 +x-1)² + (x2 +x-1) -1

= p(1) = (1+1-1)² + (1+1-1) -1

= 1

Hence, p(1) = 1

Learn more about the sum of roots here brainly.com/question/10235172

#SPJ4

8 0
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