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Tanzania [10]
3 years ago
14

What is the approximate solution to this equation?

Mathematics
2 answers:
Sindrei [870]3 years ago
5 0

Answer: b)

Step-by-step explanation:

3^3 is equal to 27 exactly, but it asks for an approximate. 27.55 is near 27 so yea, there ya go ^

ankoles [38]3 years ago
4 0
B: the cube root of 27.55 is rounded to 3

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Hi im so good at algebra i can replace your x and you wouldnt even know y
Naddika [18.5K]

Answer:

If you were words on a page, you'd be <em>Fine Print.</em>

6 0
3 years ago
PLEASE HELP ASAP !!
wariber [46]

Answer:

     <u>First figure:</u>            954cm^3

     <u>Second figure:</u>      1,508yd^3

     <u>Third figure:</u>

  •          Height= q
  •           Side length = r

     <u>Fourth figure: </u>        726cm^3

Explanation:

<u></u>

<u>A. First figure:</u>

<u>1. Formula:</u>

            \text{Volume of a cylinder}=\pi \times radius^2\times length

<u>2. Data:</u>

  • radius = 9cm / 2 = 4.5cm
  • length = 15 cm

<u>3. Substitute in the formula and compute:</u>

          Volume=\pi \times (4.5cm)^2\times (15cm)\approx 954cm^3\approx 954cm^3

<u>B. Second figure</u>

<u>1. Formula: </u>

       \text{Volume of a leaned cylinder}=\pi \times radius^2\times height

<u>2. Data:</u>

  • radius = 12yd
  • height = 40 yd

<u>3. Substitute and compute:</u>

      Volume=\pi \times (12yd)^2\times (40yd)\approx 1,507.96yd^3\approx 1,508yd^3

<u></u>

<u>C) Third figure</u>

a) The<em> height </em>is the segment that goes vertically upward from the center of the <em>base</em> to the apex of the pyramid, i.e.<u>  </u><u>q  </u>.

The apex is the point where the three leaned edges intersect each other.

b) The side length is the measure of the edge of the base, i.e.<u>  r </u><u> </u>.

When the base of the pyramid is a square the four edges of the base have the same side length.

<u>D) Fourth figure</u>

<u>1. Formula</u>

The volume of a square pyramide is one third the product of the area of the base (B) and the height H).

          Volume=(1/3)B\times H

<u>2. Data: </u>

  • height: H = 18cm
  • side length of the base: 11 cm

<u>3. Calculations</u>

a) <u>Calculate the area of the base</u>.

The base is a square of side length equal to 11 cm:

          \text{Area of the base}=B=(11cm)^2=121cm^2

b) <u>Volume of the pyramid</u>:

         Volume=(1/3)B\times H=(1/3)\times 121cm^2\times 18cm=726cm^3

4 0
3 years ago
Read 2 more answers
A sphere has a radius of 5.3 ft. What is the volume of the sphere to the nearest tenth? use 3.14 for pi. Question 3 options:
Alenkinab [10]
Your answer would be c
623.3 ft^3
5 0
2 years ago
F(x)= x^2<br><br> g(x)= (x-9)^2+3
Leviafan [203]

Answer:

Bro look it up

Step-by-step explanation:

On google

3 0
3 years ago
Some please help and explain the steps. Tysmmmmm
-Dominant- [34]

Answer:

since angle B and angle C contains the same arc AD. set the angles equal

11x-3=8x+15

x=6

so the angle has a measure of 63 degrees

the central angle is the angle of the arc

and it is always 2 times the angle that we just that contains the arc but does touches the end of the circle.

so its 63 *2 =126 degrees.

5 0
2 years ago
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