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devlian [24]
2 years ago
8

An expression is shown. 5 + 8 x 6 + 5 Create an equivalent expression, that includes a set of parentheses, so that the value of

the expression is 93.
Mathematics
2 answers:
stepan [7]2 years ago
6 0

Answer:

if u need help go to math  way

Step-by-step explanation:

math   way  is a good way to get the steps and answer to ur problem

Ad libitum [116K]2 years ago
6 0

Answer:

5 + 8 x (6 + 5) = 93

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Solve for k. k/2 +1/2=3
ikadub [295]

Answer:

k = 5

Step-by-step explanation:

Solve for k :

\frac{k}{2} + \frac{1}{2} = 3

-Multiply both sides of the equation by the denominator 2 :

2 \times \frac{k}{2} + \frac{1}{2} = 3 \times 2

k + 1 = 6

-Subtract both sides by 1:

k + 1 - 1 = 6 - 1

k = 5

So, the value of k is 5.

7 0
2 years ago
Asanji left the science museum and drove toward the lake at an average speed of 45 km/h. Sometime later Huong left driving in th
Cloud [144]

Answer:

Asanji drove for 5 hours before Huong caught up

Step-by-step explanation:

Let the time for which Asanji drove alone is "X" hours

Asanji and Huong met after three hours of driving of Huong.

Total time for which Asanji drove = X+3 hours

Thus, distance travelled by Asanji in X+3 hours is equal to distance travelled by Huong in 3 hours

45 ( X+3) = 75 (3)\\

On solving the above equation, we get -

45 X + (45 *3) = 75 *3\\45 X = (75-45)*3\\45 X = 30 *3 \\X = \frac{30 *3}{45} \\X = 2

Asanji drove for 3 + 2 = 5 hours before Huong caught up

8 0
3 years ago
What is the perimeter and area for the glowing figure?
nadya68 [22]

Answer:

Area=15

Perimeter=16

Step-by-step explanation:

First, section the shape off by easier work with shapes.

The two end triangles can then form one large rectangle that is 5in. x 3in.

Next just multiply the length times the width for the area which is 15 in., and add all of the sides up, which will give you 16 in.

8 0
2 years ago
Find the measure of <2.
n200080 [17]

Answer:

\displaystyle 90° = m∠2

Step-by-step explanation:

In every rhombus, when you have two diagonal segment bisectors, you will always have a circumcentre showing all midpoints of both segment bisectors, plus, it measures 90° all around, so with that being said, you have your answer.

I am joyous to assist you anytime.

6 0
3 years ago
What would prove that the two triangles are<br> congruent?
aniked [119]
The lines on the sides!
5 0
3 years ago
Read 2 more answers
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