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3 years ago

Under the best conditions, a sprout has a 40% probability of blooming.

Mathematics

1 answer:

murzikaleks [220]3 years ago

7 0

Answer:

Step-by-step explanation:

Im good at math

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Write a function for the tranformations described below:

IrinaK [193]

The function after the transformation has an equation of y = ∛(x - 7) + 5

<h3>How to determine the equation of the transformation?</h3>

The transformation statement is given as

"The cubic function shifts 7 units right and 5 units up."

A cubic function is represented as

y = ∛x

So, the transformations are:

Shifts 7 units right
Shift 5 units up

Mathematically, this can be represented as

(x, y) = (x - 7, y + 5)

So, we have the following equation

y = ∛(x - 7) + 5

Hence, the equation of the transformation is y = ∛(x - 7) + 5

Read more about transformation at

brainly.com/question/4280198

#SPJ1

8 0

1 year ago

The probability that a student correctly answers on the first try (the event

Lynna [10]

Check attached file for solution.

6 0

3 years ago

The sample consisted of 50 night students, with a sample mean GPA of 3.02 and a standard deviation of 0.08, and 25 day students,

bulgar [2K]

Answer: The test statistic is t= -0.90.

Step-by-step explanation:

Since we have given that

n₁ = 50

n₂ = 25

$\bar{x_1}=3.02\\\\\bar{x_2}=3.04\\\\\sigma_1=0.08\\\\\sigma_2=0.06$

So, s would be

$s=\sqrt{\dfrac{n_1\sigma_1^2+n_2\sigma_2^2}{n_1+n_2-2}}\\\\s=\sqrt{\dfrac{50\times 0.08^2+25\times 0.06^2}{50+25-2}}\\\\s=0.075$

So, the value of test statistic would be

$t=\dfrac{\bar{x_1}-\bar{x_2}}{s(\dfrac{1}{n_1}+\dfrac{1}{n_2})}\\t=\dfrac{3.02-3.04}{0.074(\dfrac{1}{50}+\dfrac{1}{25})}\\\\t=\dfrac{-0.04}{0.074(0.02+0.04)}\\\\t=\dfrac{-0.04}{0.044}\\\\t=-0.90$

Hence, the test statistic is t= -0.90.

7 0

3 years ago

Explain how to model the problem with algebra tiles and

gregori [183]

Answer:someone answer the question already

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

I have no idea how to do this, it is due in two days. Hopefully someone sees this before then.

elena-14-01-66 [18.8K]

Hello,

$m\ \widehat{ABC}=x\\m\ \widehat{BAC}=2*x\\\\So:\\ x+2x=90^o\\x=30^o\\$

$cos(30^o)=\dfrac{\sqrt{3} }{2} \\$

In the triangle ABC,

$cos(30^o)=\frac{BC}{BA} \\\\BA=\dfrac{cos(30^o)}{BC} \\\\BA=\frac{\dfrac{\sqrt{3} }{2} }{24} =16*\sqrt{3} \\\\$

$sin(30^o)=\dfrac{1 }{2} =\dfrac{AC}{AB} \\\\AC=\dfrac{1}{2} *16\sqrt{3} =8\sqrt{3}$

In the triangle ACB,

$cos(30^o)=\dfrac{AC}{AL} \\\\AL=\dfrac{8\sqrt{3} *2}{\sqrt{3} } =16\\$

6 0

3 years ago