Formula for distance between two points:
d = √((x₂-x₁)² + (y₂-y₁)²)
Let point 1 be (-3, 11) and point 2 be (5, 5)
Therefore x₁ = -3, y₁ = 11, x₂ =5, y₂ = 5, and substituting in the formula above.
d = √((x₂-x₁)² + (y₂-y₁)²)
= √((5- -3)² + (5-11)²)
= √((5+3)² + (5-11)²)
= √((8)² + (-6)²) 8² = 8*8 = 64, (-6)² = -6*-6 = 36
= √(64 + 36)
= √(100)
= 10
Distance = 10 units.
Answer:
5x+2y =-6 ........1
3x-2y = 22 ........2
Add both Equations
we get
8x = 16
Divide both sides by 8
x = 2
Substitute x = 2 into any of the equations
3(2) - 2y = 22
-2y = 22 - 6
- 2y = 18
Divide both sides by -2
y = - 9
x = 2 y = - 9
Hope this helps
Answer:
Yeah
Step-by-step explanation:
I’m pretty sure that it’s the third answer (q^12)! :)
