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2 years ago

Please answer correctly this is for a test plus you get 10 points

Mathematics

1 answer:

Korvikt [17]2 years ago

8 0

The answer to the question is 112°

First, you must set up an equation to find x.

$2(3x+10)+2(2x)=360\\$

Then, you must use distributive property to simplify the parentheses.

$6x+20+4x=360$

Next, add like terms.

$10x+20=360$

Then, subtract 20 on each side.

$10x=340$

Next, divide 10 on each side.

$x=34$

Now, you must substitute 34 in for x.

$3x+10$

$3(34)+10$

$3(34)+10=112$

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siniylev [52]

Answer:

<h2>no solution</h2>

Step-by-step explanation:

$-x^2-9\geq0\qquad\text{change the signs}\\\\x^2+9\leq0\\\\\text{the parabola}\ x^2\ \text{is op}\text{en up and shifted 9 units up. Therefore is whole}\\\text{over the x-axis (only positive values)}.\\\\\bold{CONCLUSION}:\\\\\bold{no\ solution}$

5 0

3 years ago

Find the value of x.<br> (x + 30)

taurus [48]

Answer:

x=55

Step-by-step explanation:

The exterior angles of a polygon add to 360.

x+x+x+x+x+x+30 = 360

Combine like terms

6x+30 = 360

Subtract 30 from each side

6x+30-30 = 360-30

6x = 330

Divide by 6

6x/6 =330/6

x =55

8 0

2 years ago

Montel collected 26Leaves for his science project he wants to put six leaves on a page how it shows how many pages Montello need

andrey2020 [161]

Answer:

4.3 pages

beacause 26 divided by 6 is 4.3

7 0

2 years ago

Work out the volume of the shape

pashok25 [27]

Answer:

$\large\boxed{V=\dfrac{1,421\pi}{3}\ cm^3}$

Step-by-step explanation:

We have the cone and the half-sphere.

The formula of a volume of a cone:

$V_c=\dfrac{1}{3}\pi r^2H$

r - radius

H - height

We have r = 7cm and H = (22-7)cm=15cm. Substitute:

$V_c=\dfrac{1}{3}\pi(7^2)(15)=\dfrac{1}{3}\pi(49)(15)=\dfrac{735\pi}{3}\ cm^3$

The formula of a volume of a sphere:

$V_s=\dfrac{4}{3}\pi R^3$

R - radius

Therefore the formula of a volume of a half-sphere:

$V_{hs}=\dfrac{1}{2}\cdot\dfrac{4}{3}\pi R^3=\dfrac{2}{3}\pi R^3$

We have R = 7cm. Substitute:

$V_{hs}=\dfrac{2}{3}\pi(7^3)=\dfrac{2}{3}\pi(343)=\dfrac{686\pi}{3}\ cm^3$

The volume of the given shape:

$V=V_c+V_{hs}$

Substitute:

$V=\dfrac{735\pi}{3}+\dfrac{686\pi}{3}=\dfrac{1,421\pi}{3}\ cm^3$

7 0

2 years ago

A new phone system was installed last year to help reduce the expense of personal calls that were being made by employees. Befor

Leya [2.2K]

Using the normal distribution, it is found that there was a 0.9579 = 95.79% probability of a month having a PCE between $575 and $790.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

$\mu = 700, \sigma = 50$ .

The probability of a month having a PCE between $575 and $790 is the <u>p-value of Z when X = 790 subtracted by the p-value of Z when X = 575</u>, hence:

X = 790:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{790 - 700}{50}$

Z = 1.8

Z = 1.8 has a p-value of 0.9641.

X = 575:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{575 - 700}{50}$

Z = -2.5

Z = -2.5 has a p-value of 0.0062.

0.9641 - 0.0062 = 0.9579.

0.9579 = 95.79% probability of a month having a PCE between $575 and $790.

More can be learned about the normal distribution at brainly.com/question/4079902

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3 0

1 year ago