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lakkis [162]
3 years ago
14

Are my state symbols correct?

Chemistry
1 answer:
Sonbull [250]3 years ago
7 0

they look correct I think I am right :)

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The diagram below shows the different phase transitions that occur in matter.
GarryVolchara [31]

Answer : Option A) Molecules are speeding up during boiling.

Explanation : As shown in the above image it is clearly observed that the molecules are been transformed from liquid to gaseous state. Which means that the intermolecular distance between the molecules is increasing as they are boiling and getting transformed into gaseous form. They are speeding up to form gas from liquid state and achieve stability as the heat is supplied in greater amount. Boiling of liquid is causing the liquid molecules to speed up and get transformed into gaseous molecules.

5 0
3 years ago
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Help me make a hypothesis out of this question for my project.
Lubov Fominskaja [6]
Animals are able to see much more clearly in the dark than humans can.

Or

Humans are able to see much more clearly in the dark than animals can.
7 0
4 years ago
What is your opinion on Mercury element
elixir [45]

Answer:

Mercury is an liquid metal

Explanation:

Mercury is a chemical element with the symbol Hg and atomic number 80. It is commonly known as quicksilver and was formerly named hydrargyrum.

Symbol: Hg

7 0
3 years ago
Which of the following can explain the daily change in sea level observed along a coast?
Paul [167]
The answer is: <span>A.The gravitational pull of the moon on the water near the coast </span>
4 0
3 years ago
Part A In a particular experiment at 300 ∘C, [NO2] drops from 0.0138 to 0.00886 M in 374 s . The rate of disappearance of NO2 fo
sweet-ann [11.9K]

Answer:

The rate of disappearance of NO_2 for this period is-1.32\times 10^{-5} M/s

Explanation:

Initial concentration of NO_2 = x = 0.0138 M

Final concentration of NO_2 = y = 0.00886 M

Time elapsed during change in concentration = Δt = 374 s

Change in concentration ,\Delta [NO_2]= y - x = 0.00886 - 0.0138 M = -0.00494 M

The rate of disappearance of NO_2 for this period is:

\frac{\Delta [NO_2]}{\Delta t}=\frac{-0.00494 M}{374 s}=-1.32\times 10^{-5} M/s

4 0
3 years ago
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