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Mashcka [7]
4 years ago
6

Why are ionic solids poor conductors of electricity

Chemistry
1 answer:
marshall27 [118]4 years ago
3 0

Answer:

Ionic compounds don't conduct electricity very well because the charge carriers can't move through the crystal. They can conduct heat because the kinetic energy itself is the "heat carrier”.

Hope this helps :)

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HELP THIS IS SCIENCE (No links or I'll rip off your fingers)
balu736 [363]

Answer:

D

Explanation:

Silver is a metal with high conductivity ....

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3 0
3 years ago
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Mama L [17]

Answer:

b. decreases

C. neither a physical change nor a chemical change

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6 0
4 years ago
_________based on religious beliefs
juin [17]
It may be faith.  So it faith is in your word bank then that's probably it, and if faith isn't in the word bank, then I will need to know the words that are in the word bank.
5 0
4 years ago
Which reactant is unlikely to produce the indicated product upon strong heating?
Ilya [14]

2-Methyl-4-oxo-pentanoic acid  is unlikely to produce 2-Methyl-3-butanone upon strong heating.

Upon heating, the β ketoacid becomes unstable and decarboxylates, leading to the formation of the methyl ketone.

A carboxylic acid is an organic acid that contains a carboxyl group (C(=O)OH) attached to an R-group. The general formula of a carboxylic acid is R−COOH or R−CO2H, with R referring to the alkyl, alkenyl, aryl, or other group.

Carboxylic acids occur widely. Important examples include the amino acids and fatty acids. Deprotonation of a carboxylic acid gives a carboxylate anion.

Full question :

Q.  Which reactant is unlikely to produce the indicated product upon strong heating?

  • A) 2,2-Dimethylpropanedioic acid 2-methylpropanoic acid
  • B) 2-Ethylpropanedioic acid Butanoic acid
  • C) 2-Methyl-3-oxo-pentanoic acid 3-Pentanone
  • D) 2-Methyl-4-oxo-pentanoic acid 2-Methyl-3-butanone
  • E) 4-Methyl-3-oxo-heptanoic acid 3-Methyl-2-hexanone

Hence, option (D) is correct.

Learn more about carboxylic acid here : brainly.com/question/26855500

#SPJ4

8 0
2 years ago
75 mL of water is added to a 360 mL solution of acetic acid with a concentration of 0.87 M. Determine the molarity of the new so
kramer

Answer:

The molarity of the new solution is 0.72 M

Explanation:

Step 1: Data given

Volume of the original solution = 360 mL =.360 L

Molarity = 0.87 M

We add 75 mL = 0.075 L

Step 2: Calculate moles

Moles = molarity * volume

Moles = 0.87 M * 0.360 L

Moles = 0.3132 moles

Step 3: Calculate new molarity

The number of moles stays constant

Molarity = moles / volume

Molarity = 0.3132 moles / (0.36+0.075)

Molarity = 0.3132 moles / 0.435 L

Molarity = 0.72 M

The molarity of the new solution is 0.72 M

3 0
3 years ago
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