Step-by-step explanation:
Assuming the data is as shown, restaurant X has a mean service time of 180.56, with a standard deviation of 62.6.
The standard error is SE = s/√n = 62.6/√50 = 8.85.
At 95% confidence, the critical value is z = 1.960.
Therefore, the confidence interval is:
180.56 ± 1.960 × 8.85
180.56 ± 17.35
(163, 198)
Restaurant Y has a mean service time of 152.96, with a standard deviation of 49.2.
The standard error is SE = s/√n = 49.2/√50 = 6.96.
At 95% confidence, the critical value is z = 1.960.
Therefore, the confidence interval is:
152.96 ± 1.960 × 6.96
152.96 ± 13.64
(139, 167)
Answer:
The required probability is, 0.78
Step-by-step explanation:
There are, (52 - 13) = 39 cards which are not spade
5 cards can be chosen from the deck of 52 cards in
ways
and out of these 5 choices, none of them will be spade in,
ways
So,
P(None of the chosen cards is spade)
= 

Hence,
P(out of these 5 choices, at least one card is spade)

= 0.78
The midpoint of (x1,y1) and (x2,y2) is

just average them
(4,1) and (-2,4)
the midpoint is

(1,-1.5)
Answer:
x=2/5
Step-by-step explanation: