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Elodia [21]
3 years ago
15

Osvoldo has a goal of getting at least 30% of his grams of carbohydrates each day from whole grains. Today he ate 220 grams of c

arbohydrates and 55 grams were from whole grains
Did Osvoldo meet his goal, why?
Yes/no osvoldo ate. Grams of whole grains more/less than his goal
Mathematics
2 answers:
Ahat [919]3 years ago
5 0

Answer:

Step-by-step explanation:

I can not figure it out on khan academy need some help

LekaFEV [45]3 years ago
3 0
Envenenan i don’t know
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The manufacturer of an electronic device claims that the probability of the device failing during the warranty period is 0.005.
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Answer:

The  value is  P(X \ge  15) =  0.5

Step-by-step explanation:

From the question we are told that

    The probability of the device failing during the warranty period is p =  0.005

    The  sample size is  n = 3000

     The random variable  considered is  x  =  15

Generally this is distribution is binomial given the fact that there is only two out comes hence

      X  which is a variable representing a randomly selected selected electronic follows a binomial distribution i.e

     X  \~ \  B(n , p)

Now the mean is mathematically evaluated as

      \mu  =  n *  p

=>   \mu  = 3000 *  0.005

=>    \mu  =15

The standard deviation is mathematically represented as

      \sigma  =  \sqrt{np(1 -p )}

=>  \sigma  =  \sqrt{3000 *  0.005 * (1 - 0.005 )}

=>   \sigma  =  3.86

Now given that n is very large, then it mean that we can successfully apply normal approximation on this  binomial distribution

So

    P(X \ge  15) =  P( \frac{X - \mu}{\sigma }  \ge \frac{x - \mu}{\sigma } )

Now  applying  Continuity Correction we have

   P(X \ge  (15-0.5)) =  P( \frac{X - \mu}{\sigma }  > \frac{(15 -0.5) - 15}{3.86 } )

Generally  \frac{X - \mu}{\sigma }   =  Z (The \ standardized \ value  \ of  \ X)

    P(X \ge  (15-0.5)) =  P(Z >-0.130 )

From the z-table  

       P(Z >-0.130 )  =0.5

Thus  

    P(X \ge  15) =  0.5

 

   

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=7^2

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