All categories

3 years ago

3.6 is less then or greater then 12/5

Mathematics

2 answers:

ra1l [238]3 years ago

8 0

It is greater than because 12/5 = 2 2/5 which is equal to 2.4. 3.6 is greater than 2.4

andrew11 [14]3 years ago

7 0

3.6 is greater than 12/5 because 12/5 as a decimal is 2.4

You might be interested in

What is the volume of a cube with 1/3 in sides

Dimas [21]

Answer:

V equal a3

Step-by-step explanation:

3 0

4 years ago

-2×-7y=30 <br>7×+4y=18 <br>×= <br>y=

Sati [7]

Answer:

Answer is -7 Hope this helps :D

Step-by-step explanation:

6 0

3 years ago

How to do question 1?Had no idea how to do both parts

givi [52]

$y=\dfrac{\ln x}{3x-6}$

Differentiate both sides with respect to $x$ :

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{3x-6}x-3\ln x}{(3x-6)^2}$

When $x=1$ , you have

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{3-6}1-3\ln1}{(3-6)^2}=\dfrac{-3}9=-\dfrac13$

For part (b), we now assume that $x$ and $y$ are functions of an independent variable, which we'll call $t$ (for time). Now differentiating both sides with respect to $t$ , we have

$\dfrac{\mathrm dy}{\mathrm dt}=\dfrac{\frac{3x-6}x-3\ln x}{(3x-6)^2}\dfrac{\mathrm dx}{\mathrm dt}$

where the chain rule is used on the right side. We're told that $y$ is decreasing at a constant rate of 0.1 units/second, which translates to $\dfrac{\mathrm dy}{\mathrm dt}=-0.1$ . So when $x=1$ , you have

$-0.1=\dfrac{\frac{3-6}1-3\ln1}{(3-6)^2}\dfrac{\mathrm dx}{\mathrm dt}$
$-0.1=-\dfrac13\dfrac{\mathrm dx}{\mathrm dt}$
$\dfrac{\mathrm dx}{\mathrm dt}=0.3$

where the unit is again units/second.

6 0

3 years ago

100 POINTS !! The trajectory of a potato launched from a potato cannon on the ground at an angle of 45 degrees with an initial s

stellarik [79]

Answer:

height: 125m; distance: 500m

Step-by-step explanation:

x = 250

f(x) = x − 0.002x2

f(x) = 250 − 0.002(250 )2

= 250 − 0.002(62,500)

= 250 − 125

= 125

250 times 2 = 500

6 0

3 years ago

Read 2 more answers

Danielle construct a scale model of a building with a rectangular base her model is 2 inches in length and 1 inch in width the s

Kitty [74]

Given:

a.) The scale of the model is 1 in equals 47 ft.

b.) Danielle constructs a scale model of a building with a rectangular base her model is 2 inches in length and 1 inch in width.

To be able to determine the actual area of the base, let's first identify the actual dimensions of the base.

We get,

$\text{Length: 2 (inches) x }\frac{47\text{ ft.}}{1\text{ (inch)}}\text{ = 2 x }\frac{47\text{ ft.}}{1}\text{ = 94 ft.}$ $\text{Width: 1 (inch) x }\frac{47\text{ ft.}}{1\text{ (inch)}}\text{ = 1 x }\frac{47\text{ ft.}}{1}\text{ = 47 ft.}$

Let's now solve for the area of the base, since it is a rectangle, we will be using the formula below:

$\text{ Area = L x W ; where L = Length and W = Width}$

We get,

$\text{ Area = L x W}$ $\text{ = 94 ft. x 47 ft.}$ $\text{ Area = 4,418 ft.}^2$

Therefore, the actual area of the base is 4,418 ft.².

7 0

1 year ago