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alexandr1967 [171]
3 years ago
11

-2×-7y=30 7×+4y=18 ×= y=​

Mathematics
1 answer:
Sati [7]3 years ago
6 0

Answer:

Answer is -7      Hope this helps :D

Step-by-step explanation:

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How do I simplify the expression
stiks02 [169]
ANSWER: ab√3ac

Is this enough for you ?

5 0
3 years ago
Is -3 a natural number a whole number a integer a rational number or irrational number
BaLLatris [955]

Answer:

-3 is a rational integer.

Step-by-step explanation:

An integer is a superset of the whole numbers that includes the negated values as well as 0.

A rational number is simply anything that can be expressed as a fraction.

-3 is by these definitions, a negated 3, and any non fractional number can be expressed as a fraction.

-3 is not a natural number, as that is the set of numbers {1, 2, 3, 4, 5, ... etc} and -3 is not a whole number, as that is the set of numbers {0, 1, 2, 3, 4, ... etc}.

And -3 is also not an irrational number since it can be expressed as a fraction.

Thus, -3 is a rational integer.

Cheers.

7 0
3 years ago
HELP PLSSSSS PLSSSS I NEED HELPPPPPPP ASAPPPPP
Hitman42 [59]
I would say A (7) but I’m not 100% sure.
5 0
2 years ago
A forester studying diameter growth of red pine believes that the mean diameter growth will be different from the known mean gro
-Dominant- [34]

Answer:

t=\frac{1.6-1.35}{\frac{0.46}{\sqrt{32}}}=3.07  

The degrees of freedom are given by:

df =n-1= 32-1=31

Since is a two-sided test the p value would be:  

p_v =2*P(t_{31}>3.07)=0.0044  

Since the p value is a very low value we have enough evidence to conclude that true mean is significantly different from 1.35 in/year at any significance level commonly used for example (\alpha=0.01,0.05, 0.1, 0.15).

Step-by-step explanation:

Data given and notation  

\bar X=1.6 represent the sample mean

s=0.46 represent the sample deviation

n=32 sample size  

\mu_o =1.35 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is different from 1.35 in/year, the system of hypothesis would be:  

Null hypothesis:\mu =1.35  

Alternative hypothesis:\mu \neq 1.35  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{1.6-1.35}{\frac{0.46}{\sqrt{32}}}=3.07  

P-value  

The degrees of freedom are given by:

df =n-1= 32-1=31

Since is a two-sided test the p value would be:  

p_v =2*P(t_{31}>3.07)=0.0044  

Since the p value is a very low value we have enough evidence to conclude that true mean is significantly different from 1.35 in/year at any significance level commonly used for example (\alpha=0.01,0.05, 0.1, 0.15).

5 0
3 years ago
Some registered nurses earn $141.75 for working 4.5 hours. What is the hourly rate?
Blizzard [7]
The hourly rate is $31.50
4 0
3 years ago
Read 2 more answers
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