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marin [14]
3 years ago
10

How do I solve 5 1/2 divided by -2 3/4

Mathematics
2 answers:
DanielleElmas [232]3 years ago
8 0
5.5/-2.75
=-2
20 charrrrrrrrrrrrrrrrrr
rusak2 [61]3 years ago
7 0
5\frac{1}{2}:(-2\frac{3}{4 })= \frac{11}{2}:(-\frac{11}{4})= \frac{\not11^1}{\not2^1}*(-\frac{\not4^2}{\not11^1})=-2


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Valeria has been training for the Charlestown cruisers bike race. The first week she trained, she rode 5 days and took the same
ira [324]

The number of miles covered every evening obtujwd using a <em>system of equation</em> is 15 miles.

<u>Let the number of miles per evening</u> = m

  • Number of days = 5

  • Number of miles per morning = 8 miles

  • Total miles covered = 115 miles

<u>Using the expression below :</u>

<em>Number of days(miles per morning + miles per evening) = 115 miles </em>

5(8 + m) = 115

40 + 5m = 115

5m = 115 - 40

5m = 75

m = 75 / 5

m = 15 miles

Therefore, the Number of miles covered per evening is 15 miles.

Learn more : brainly.com/question/18796573

8 0
3 years ago
Please solve thanks!
Alona [7]

Answer:

f(-3)=4

b

Step-by-step explanation:

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7 0
3 years ago
Solve for the value of z: 14/5 = z/24<br> ____?
natka813 [3]

Answer:

Step-by-step explanation:

Cross multiplying

5z =14*24

5z = 336

Divide by 5

z = 336/5

Or mixed fraction z= 67(1/5)

Decimal z= 67.2

3 0
3 years ago
Read 2 more answers
Need help asap please!
Montano1993 [528]

Answer:

  • determinant: -15
  • x = 3; y = 4; z = 1

Step-by-step explanation:

The matrix of coefficients has one row corresponding to each equation. The constants in that row are the coefficients of the variables in the equation. Coefficients are listed in the same order on each row. A missing term is represented by a coefficient of 0.

<h3>coefficient matrix, determinant</h3>

The first attachment shows the coefficient matrix and its determinant.

__

<h3>solution</h3>

The solution to the system of equations can be found by left-multiplying the constant vector by the inverse of the coefficient matrix.

  \textbf{A$\cdot$X}=\textbf{B}\\\\\textbf{X}=\textbf{A}^{-1}\cdot\textbf{B}

This multiplication is shown in the second attachment. It tells us ...

  \textbf{X}=\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{c}3\\4\\1\end{array}\right]

4 0
2 years ago
I givee brainlilstttt
Anastasy [175]

Answer:

A

Step-by-step explanation:

4 0
3 years ago
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