Please solve thanks!

Conference A and conference B each have 10 football teams. The table shows the number of football games that each team in the tw

babymother [125]

Answer with explanation:

1.Mean of a Data set

$=\frac{\text{Sum of all the observation}}{\text{total number of observation}}$

$=\frac{10+9+11+8+10+12+2+7+8+0+12+10+8+11+3+12+6+7+4+3}{20}\\\\=\frac{153}{20}\\\\=7.65$

2. Range = Maximum value in two conferences - Minimum value in two conference

= 12 - 0

=12

The mean number of wins for teams from the two conferences is 7.65.

The range in wins is 12.

3 0

3 years ago

Read 2 more answers

Is this question correct?

Andrews [41]

Answer:

10^20

3^11

3^24

10^12

Step-by-step explanation:

(10^2)^10=10^2*10=10^20

3^3*3^8=3^3+8=3^11

(3^3)^8=3^3*8=3^24

10^2*10^10=10^2+10=10^12

6 0

3 years ago

a rectangular sheet is 62cm long and 42cm wide from each of its corners a square of side 6cm is cut out and an open box is made

Alla [95]

Answer:

The volume of rectangular box is 9,000 cubic centimeters

Step-by-step explanation:

Given as :

The length of the rectangular sheet = L = 62 cm

The width of the rectangular sheet = B = 42 cm

Let The volume of rectangular box = v cubic centimeters

From each corner of sheet a square of 6 cm is cut out and an open box made

So, The length of box = L' = (L - 6 - 6)

i.e L' = (62 - 6 - 6)

Or, L' = 50 cm

Or, Length of the box = 50 cm

And The width of the box = B' = (B - 6 - 6)

i.e B' = (42 - 6 - 6)

Or, B' = 30 cm

Or width of the box = 30 cm

And,

The height of the box = H = 6 cm

∴ volume of rectangular box = Length of box × Breadth of box × Height of box

i.e v = L' × B' × H

Or, v = 50 cm × 30 cm × 6 cm

Or, v = 9,000 cm³

So, The volume of rectangular box = v = 9,000 cm³

Hence, The volume of rectangular box is 9,000 cubic centimeters Answer

4 0

3 years ago

Find P on AB that is 2/3 of the distance from A(-3,-5) to B(9,4).

Ludmilka [50]

A line segment can be divided into ratios.

The coordinate of P on line segment AB is (5,1)

Given

$A = (-3,-5)$

$B = (9,4)$

The position of P from A to B is:

$P_A = \frac 23$

So, from P to B would be:

$P_B =1 - \frac 23$

$P_B = \frac 13$

So, the ratio is:

$m : n = \frac 23 : \frac 13$

Simplify

$m : n = 2 :1$

The coordinate of point P is:

$P = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})$

So, we have:

$P = (\frac{2 \times 9 + 1 \times -3}{2 + 1},\frac{2 \times 4 + 1 \times -5}{2 + 1})$

$P = (\frac{15}{3},\frac{3}{3})$

$P = (5,1)$

Hence, the coordinate of P is (5,1)

Read more about line ratios at:

brainly.com/question/8847082

8 0

3 years ago

Fill in Sin, Cos, and tan ratio for angle x. Sin X = 4/5 (28/35 simplified)

Fantom [35]

Answer:

Given: $\sin(x) = (4/5)$ .

Assuming that $0 < x < 90^{\circ}$ , $\cos(x) = (3/5)$ while $\tan(x) = (4/3)$ .

Step-by-step explanation:

By the Pythagorean identity $\sin^{2}(x) + \cos^{2}(x) = 1$ .

Assuming that $0 < x < 90^{\circ}$ , $0 < \cos(x) < 1$ .

Rearrange the Pythagorean identity to find an expression for $\cos(x)$ .

$\cos^{2}(x) = 1 - \sin^{2}(x)$ .

Given that $0 < \cos(x) < 1$ :

$\begin{aligned} &\cos(x) \\ &= \sqrt{1 - \sin^{2}(x)} \\ &= \sqrt{1 - \left(\frac{4}{5}\right)^{2}} \\ &= \sqrt{1 - \frac{16}{25}} \\ &= \frac{3}{5}\end{aligned}$ .

Hence, $\tan(x)$ would be:

$\begin{aligned}& \tan(x) \\ &= \frac{\sin(x)}{\cos(x)} \\ &= \frac{(4/5)}{(3/5)} \\ &= \frac{4}{3}\end{aligned}$ .

7 0

2 years ago