I assume the equation is supposed to be
Then we can write
Take the logarithm of base 3/8 on both sides:
- - -
If the equation is actually , I'm afraid it cannot be solved exactly.
Please solve thanks!
1 answer:
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Please find the attached file for a better understanding of the explanation given here.
the attached diagram is a generated image of the first fifteen rows of a pascal's triangle. As can be seen from the image, the least four-digit number in the first fifteen rows of pascal's triangle is 1001.
In the diagram attached that number is present in the very last row and is highlighted using a yellow rectangle.
For this, I'll be using the substitution method. Since y = 1/3x - 6, replace the y variable in the first equation with 1/3x - 6 and solve for x:
Now that we have the value of x, plug it into either equation to solve for y:
Answer:
Area of semicircle = 1/2(πr^2)
Area of quarter circle = 1/4(πr^2)
Step-by-step explanation:
The question is incomplete. You didn't provide the diagrams for the semicircle and quarter circle to evaluate the areas. I would explain how to find the area of a semicircle and quarter circle.
Area of a circle = πr^2
where r = radius and π = 3.14
If diameter (d) is given: d = 2r
To get radius, divide diameter by 2.
r = d/2
A semicircle is half of a circle.
Area of a semicircle is half the area of a circle.
Area of a semicircle = 1/2(πr^2)
A quarter circle is a quarter of a circle.
Area of a quarter circle is quarter of the area of a circle.
Area of a quarter circle = 1/4(πr^2)
Further explanation with diagram has been added as as an attachment.
