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3 years ago

3x + 2x divided by 4-2

Mathematics

2 answers:

MissTica3 years ago

6 0

I think the answer might probably be 3 or 3x

Harlamova29_29 [7]3 years ago

3 0

The answer is 5x/2 because all you have to do is add 3x + 2x too make 5x and take 4-2 which is 2 and since it can't be simplified any more, just do 5x/2. Hope this helped! :)

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What line is perpendicular to y= 2x - 4

kolezko [41]

In Perpendicular product of slope is -1 so slope of y=2x-4 is 2 and 2*m=-1 m= -1/2 so y= -1/2x -4

4 0

3 years ago

Match each expression with an equivalent expression.

Marysya12 [62]

Answer:

$6x-4y$ → 4. $2(3x-2y)$

$6-4x$ → 3. $2(3-2x)$

$6x-4x$ → 1. $2x$

$6x-4$ → 2. $2(3x-2)$

Step-by-step explanation:

You need to:

Factor out 2 from $6x-4y$ , then you get the equivalent expression:

$=2(3x-2y)$ this matches with OPTION 4

Factor out 2 from $6-4y$ , then you get the equivalent expression:

$=2(3-2x)$ this matches with OPTION 3

Make the subtraction for $6x-4x$ , then you get the equivalent expression:

$=2x$ this matches with OPTION 1

Factor out 2 from $6x-4$ , then you get the equivalent expression:

$=2(3x-2)$ this matches with OPTION 2

3 0

3 years ago

Read 2 more answers

Insert <, >, or = in the appropriate space to make a true statement.

Harman [31]

Answer:

Step-by-step explanation:

1 - 3 ?? -4

-2 ?? -4

The appropriate symbol for this ?? relation is >.

1 -3 > -4

6 0

3 years ago

4) A random sample of students at Westcott Elementary were asked how many siblings they had. The following data was collected: 0

netineya [11]

A) 0
B) 6
C) middle number, or middle 2, averaged, so 3
D) 1
E) 4
F) 6-0 = 6

6 0

3 years ago

Let the number of chocolate chips in a certain type of cookie have a Poisson distribution. We want the probability that a cookie

ludmilkaskok [199]

Answer:

$\lambda \geq 6.63835$

Step-by-step explanation:

The Poisson Distribution is "a discrete probability distribution that expresses the probability of a given number of events occurring in a fixed interval of time or space if these events occur with a known constant mean rate and independently of the time since the last event".

Let X the random variable that represent the number of chocolate chips in a certain type of cookie. We know that $X \sim Poisson(\lambda)$

The probability mass function for the random variable is given by:

$f(x)=\frac{e^{-\lambda} \lambda^x}{x!} , x=0,1,2,3,4,...$

And f(x)=0 for other case.

For this distribution the expected value is the same parameter $\lambda$

$E(X)=\mu =\lambda$

On this case we are interested on the probability of having at least two chocolate chips, and using the complement rule we have this:

$P(X\geq 2)=1-P(X$

Using the pmf we can find the individual probabilities like this:

$P(X=0)=\frac{e^{-\lambda} \lambda^0}{0!}=e^{-\lambda}$

$P(X=1)=\frac{e^{-\lambda} \lambda^1}{1!}=\lambda e^{-\lambda}$

And replacing we have this:

$P(X\geq 2)=1-[P(X=0)+P(X=1)]=1-[e^{-\lambda} +\lambda e^{-\lambda}[]$

$P(X\geq 2)=1-e^{-\lambda}(1+\lambda)$

And we want this probability that at least of 99%, so we can set upt the following inequality:

$P(X\geq 2)=1-e^{-\lambda}(1+\lambda)\geq 0.99$

And now we can solve for $\lambda$

$0.01 \geq e^{-\lambda}(1+\lambda)$

Applying natural log on both sides we have:

$ln(0.01) \geq ln(e^{-\lambda}+ln(1+\lambda)$

$ln(0.01) \geq -\lambda+ln(1+\lambda)$

$\lambda-ln(1+\lambda)+ln(0.01) \geq 0$

Thats a no linear equation but if we use a numerical method like the Newthon raphson Method or the Jacobi method we find a good point of estimate for the solution.

Using the Newthon Raphson method, we apply this formula:

$x_{n+1}=x_n -\frac{f(x_n)}{f'(x_n)}$

Where :

$f(x_n)=\lambda -ln(1+\lambda)+ln(0.01)$

$f'(x_n)=1-\frac{1}{1+\lambda}$

Iterating as shown on the figure attached we find a final solution given by:

$\lambda \geq 6.63835$

4 0

3 years ago