So we are given the mean and the s.d.. The mean is 100 and the sd is 15 and we are trying the select a random person who has an I.Q. of over 126. So our first step is to use our z-score equation:
z = x - mean/s.d.
where x is our I.Q. we are looking for
So we plug in our numbers and we get:
126-100/15 = 1.73333
Next we look at our z-score table for our P-value and I got 0.9582
Since we are looking for a person who has an I.Q. higher than 126, we do 1 - P. So we get
1 - 0.9582 = 0.0418
Since they are asking for the probability, we multiply our P-value by 100, and we get
0.0418 * 100 = 4.18%
And our answer is
4.18% that a randomly selected person has an I.Q. above 126
Hopes this helps!
Answer:Yesterday, Ron helped his father
Step-by-step explanation:
The magnitude of YZ is 8.6
<u>Explanation:</u>
<u />
Y( -4, 12)
Z ( 1, 19)
Magnitude of YZ = ?
We know:
On substituting the value we get:
Thus, the magnitude of YZ is 8.6
Answer:
The probability of getting an a in both courses is 1.27
Step-by-step explanation:
Probability of getting A in Math, P(M) = 0.6
5
Probability of getting A in Science, P(S) = 0.62
Required probability of getting A in both courses, P(M and S)
= P(M) + P(S)
= 0.65 + 0.62
= 1.27
It's 57 and 59
Call (n) is the first odd interger => the second odd interger is (n+2)
=> n + (n + 2) = 116
=> n + n + 2 = 116
=> 2n = 114
=> n = 57
First odd interger is 57 and the second odd interger is 59 .
Sorry my English so bad =)))
