All categories

4 years ago

What is the prime factorization of 29?

Mathematics

2 answers:

kolbaska11 [484]4 years ago

4 0

29 is a prime number so 1 and 29 is its prime factorization numbers

goldfiish [28.3K]4 years ago

3 0

29 is a prime number so has no factors other than 1 and 29.

You might be interested in

What is the estimate of 256+321

Sati [7]

The estimate would be 2+3 5+2 and 6+1 so 577 you can also just round and do 250 +300= 550 +20=570

6 0

3 years ago

Read 2 more answers

The person at (0, 1) needs a bottled water. He moved to the right on a slope of -4. Where can you find him to give him the water

olga_2 [115]

You can find him at (-4,1)

5 0

3 years ago

What is the slope intercept ?

Olegator [25]

Answer:

y=mx+b

Step-by-step explanation:

that is the equation

4 0

3 years ago

8 is what percent of 24?

Irina18 [472]

Answer:

1, 33.3

2, 81.9

3, 240

4, the farmer sold 33.3 of his crops

5, 750 students are enrolled.

5 0

3 years ago

Read 2 more answers

Consider a system with one component that is subject to failure, and suppose that we have 115 copies of the component. Suppose f

castortr0y [4]

Answer:

Step-by-step explanation:

From the given information:

the mean $(\mu) = 115 \times 20$

= 2300

Standard deviation = $20 \times \sqrt{115}$

Standard deviation (SD) = 214.4761

TO find:

a) $P(x > 3500)= P(Z > \dfrac{3500-\mu}{214.4761})$

$P(x > 3500)= P(Z > \dfrac{3500-2300}{214.4761})$

$P(x > 3500)= P(Z > \dfrac{1200}{214.4761})$

$P(x > 3500)= P(Z >5.595)$

From the Z-table, since 5.595 is > 3.999

$P(x > 3500)=1-0.9999$

P(x > 3500) = 0.0001

Here, the replacement time for the mean $(\mu) = \dfrac{0+0.5}{2}$

= 0.25

Replacement time for the Standard deviation $\sigma = \dfrac{0.5-0}{\sqrt{12}}$

$\sigma = 0.1443$

For 115 component, the mean time = (115 × 20)+(114×0.25)

= 2300 + 28.5

= 2328.5

Standard deviation = $\sqrt{(115\times 20^2) +(114\times (0.1443)^2)}$

= $\sqrt{(115\times 400) +(114\times 0.02082249}$

= $\sqrt{(46000) +2.37376386}$

= $\sqrt{(46000) +(2.37376386)}$

= $\sqrt{46002.374}$

= 214.482

Now; the required probability:

$P(x > 4125) = P(Z > \dfrac{4125- 2328.5}{214.482})$

$P(x > 4125) = P(Z > \dfrac{1796.5}{214.482})$

$P(x > 4125) = P(Z >8.376)$

$P(x > 4125) =1- P(Z$

From the Z-table, since 8.376 is > 3.999

P(x > 4125) = 1 - 0.9999

P(x > 4125) = 0.0001

7 0

3 years ago