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dimulka [17.4K]
3 years ago
9

"A class of 30 students took midterm science exams. 20 students passed the chemistry exam, 14 students passed physics, and 6 stu

dents passed both chemistry and physics. Which Venn diagram correctly represents this information? (See attachment)
A) Venn diagram 1

B) Venn diagram 2

C) Venn diagram 3

D) Venn diagram 4"

Mathematics
2 answers:
Nana76 [90]3 years ago
6 0

Answer:

Option B). Venn diagram 2

Step-by-step explanation:

A class of 30 students took midterm science exams.

20 students passed chemistry exam, 14 passed physics and 6 students passed both physics and chemistry.

Since 6 students are common in both, so students who passed chemistry exam only will be = 20 - 6 = 14

And students who passed physics only = 14 - 6 = 8

So students who passed chemistry only are 14, students physics only are 8 and students who passed both the subjects are 6.

Moreover, students who couldn't pass any subject = 30 - (14 + 8 + 6) = 30 - 28 = 2

Option B) Venn diagram 2 is the correct option.

katen-ka-za [31]3 years ago
4 0
The answer is the letter B 
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MA=\sqrt{\left(\dfrac{\boxed{3}a}{2}\boxed{-}\boxed{0}\right)^2+\left(\dfrac{\boxed{b}}{2}\boxed{-}\boxed{0}\right)^2}=\\\\\\=&#10;\sqrt{\left(\dfrac{\boxed{3}a}{\boxed{2}}\right)^2+\left(\dfrac{b}{2}\right)^2}=\sqrt{\dfrac{\boxed{9}a^2}{\boxed{4}}+\dfrac{\boxed{b}^2}{\boxed{4}}}

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NB=\sqrt{\left(\dfrac{a}{2}\boxed{-}\boxed{2}a\right)^2+\left(\dfrac{b}{2}\boxed{-}\boxed{0}\right)^2}=\\\\\\=\sqrt{\left(\dfrac{a}{2}\boxed{-}\dfrac{\boxed{4}\boxed{a}}{2}\right)^2+\left(\dfrac{b}{2}-\boxed{0}\right)^2}=\\\\\\&#10;\sqrt{\left(\dfrac{-3a}{2}\right)^2+\left(\dfrac{b}{\boxed{2}}\right)^2}=\sqrt{\dfrac{\boxed{9}a^2}{\boxed{4}}+\dfrac{\boxed{b}^2}{\boxed{4}}}
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3 years ago
Read 2 more answers
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