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VARVARA [1.3K]
3 years ago
7

The equation mc024-1.jpg shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the su

n, A, in astronomical units, AU. If planet Y is twice the mean distance from the sun as planet X, by what factor is the orbital period increased?
mc024-2.jpg
mc024-3.jpg
mc024-4.jpg
mc024-5.jpg
Mathematics
1 answer:
lesya692 [45]3 years ago
3 0
<span>Given that the equation T^2=A^3 shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A, in astronomical units, AU.
i.e. T= \sqrt{A^3}

If planet Y is twice the mean distance from the sun as planet X,
i.e. A_Y=2A_X,
then,
\frac{T_Y}{T_X} =  \frac{\sqrt{(2A_X)^3}}{\sqrt{(A_X)^3}}  = \frac{(2A_X)^3}{(A_X)^3} = \frac{8(A_X)^3}{(A_X)^3} =8

Therefore, the orbital period increased by a factor of 2^3/2</span>
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Single-tickets sell for $20 each and a couple-tickets for $35 each. A total of 160 tickets are
Alex

Answer:

100 of the 20$ tickets, and 60 of the 35$ tickets

Step-by-step explanation:

20*x + 35*y = 4100

x + y = 160

That means x = 160 - y, put this into the first equation

20(160 - y) + 35y = 4100

3200 - 20y + 35y = 4100

15y + 3200 = 4100

15y = 900

y = 60

Put y = 60 into the second equation and

x + 60 = 160

x = 100

y = 60, x = 100

Double check that this works for both equations to make sure its right

20 * 100 + 35 * 60= 4100

2000 + 2100 = 4100 /Correct

100 + 60 = 160 /Correct

3 0
3 years ago
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The First one is the answer.

5 0
3 years ago
√16 simplify. assume that all variables are non-negative
morpeh [17]

Answer:

<em>4</em>

Step-by-step explanation:

\sqrt{16}

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Solve the equation, keeping the value for x as an improper fraction.
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Step-by-step explanation:

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3 years ago
Read 2 more answers
A mug is 1/8 full. The mug contains 1/6 of a cup of water. Find the capacity of the mug. Write the answer as a fration or mixed
Andre45 [30]

Answer:

The capacity of the mug = 1\frac{1}{3} cups

Step-by-step explanation:

Given - A mug is 1/8 full. The mug contains 1/6 of a cup of water.

To find - Find the capacity of the mug. Write the answer as a fraction or mixed number

Proof -

Let the capacity of water = x

Given that,

A mug is \frac{1}{8} full of water

⇒Total cups of water in the mug = \frac{1}{8} x

Now,

Given that, The mug contains \frac{1}{6} of a cup of water.

∴ we get

\frac{1}{8} x =  \frac{1}{6}

⇒x = \frac{1}{6} × 8

     = \frac{8}{6}

     = \frac{4}{3} = 1\frac{1}{3}

⇒x = 1\frac{1}{3}

∴ we get

The capacity of the mug = 1\frac{1}{3} cups

8 0
3 years ago
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