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Zepler [3.9K]
4 years ago
9

The distance between between two distinct points on number line is always greater than zero?

Mathematics
1 answer:
IgorC [24]4 years ago
4 0
<span>The answer here is true. It is logically impossible to create a negative distance between two lines on a number line. Even using negative numbers, there would still be a distance between the two. This also applies to a microscopic difference. At the end of the day, there is still a difference.</span>
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An animal park has lions,tigers and zebras 17% a lions 3/10 a zebras what % is the tigers
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17% are lions, 3/10 = 30% are zebras, therefore the remaining 100 - 47 = 53% of animals are tigers.
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200/160 as a percentage (200 over 160)
dem82 [27]

Answer:

80%

Step-by-step explanation:

Please brainlist me

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CAN SOMEONE PLEASE HELP ME???
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A total of 243 tickets were sold for the school play. They were either adult tickets or student tickets. The number of student t
alina1380 [7]

Answer:

81 adult tickets

Step-by-step explanation:

Step 1:

Set up a system of equations

Since the adult tickets and student tickets add to 243, we can do

a+s=243

and the student tickets sold were 2x the adult tickets, we can do

s=2a

We can replace s in the first equation adding to 243 with 2a

a+s(2a)=243\\3a=243\\

Step 2:

Solve for a. We can divide both sides by 3.

a=81

Therefore, there were 81 adult tickets sold.

Step 3:

We can check our work! Since we learned earlier the student tickets are 2x adult tickets, we can multiply 81 by 2 and add that to 81 to see if it equals 243!

s=2a\\s=2(81)\\s=162

And...

162+81=243

So, 81 must be the answer!

8 0
2 years ago
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Does someone mind helping me with this? Thank you!
zalisa [80]

\qquad\qquad\huge\underline{{\sf Answer}}

The given two polygons are similar to one another ~

Sides of the given polygons are in ratio of :

\qquad \sf  \dashrightarrow \: 28 : 4

to put in simple Ratio ~

\qquad \sf  \dashrightarrow \: 7: 1

So, the sides of the larger polygon are :

  • 4 × 7 = 28

  • 6 × 7 = 42

  • 3 × 7 = 21

  • 4 × 7 = 28

  • 7 × 7 = 49

  • 3 × 7 = 21

  • 3 × 7 = 21

  • 4 × 7 = 28

Now, to find the Perimeter of larger polygon ~ add the side length of all sides :

\qquad \sf  \dashrightarrow \:p = 28 + 42 + 21 + 28 + 49 + 21 + 21 + 28

\qquad \sf  \dashrightarrow \:238 \:  \: units

6 0
3 years ago
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