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Mashutka [201]
3 years ago
12

Which expression represents the composition [g o f o h](x) for the functions below?

Mathematics
1 answer:
Brut [27]3 years ago
7 0

Answer:

A

5(15x-4)^3

Explanation:

I assume you mean g(f(h(x))) so in that case here is how you do it:

So the first one is g(x) which is:

5x^3

Now g(f(x)) you just plug in f(x) for the x in the g equation. It would look like this:

5(5x-4)^3

Now the h(x) you would do the same, plug it in for all the values of x in g(x). So it would look like this:

5(5(3x)-4)^3

Since you simplify, you get 5(15x-4)^3

This final equation is g(f(h(x))) which is what you were looking for, which is A

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Giving brainly to correct answer
Elena L [17]

Answer:

The answer is the second one

im sorry if this is wrong

Step-by-step explanation:

4 0
3 years ago
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Use the formula for the sum of the first n terms of a geometric sequence to solve. Find the sum of the first 8 terms of the geom
Dvinal [7]

Answer:

-2040

Step-by-step explanation:

S_n=a_1\dfrac{r^n-1}{r-1} \qquad\text{for first term $a_1$ and common ratio r}\\\\S_8=-8\dfrac{2^8-1}{2-1}=-2040

The sum of the first 8 terms is -2040.

8 0
4 years ago
A care care company sells 45in. Upholstery fabric for car restoration. Art bought 7 1/4 yd and 12 9/10 yd for two car projects.
Troyanec [42]

Answer: the number of yards that art bought is 20 3/20 yards

Step-by-step explanation:

Art bought 7 1/4 yd and 12 9/10 yd for two car projects. We would convert both measurements from mixed fraction to improper fraction before adding.

Converting 7 1/4 yd to improper fraction, it becomes 29/4

Converting 12 9/10 yd to improper fraction, it becomes 129/10 yd

Adding both measurements, it becomes

29/4 + 129/10 = (145 + 258)/20 = 403/20yds

Converting to mixed fraction, it becomes

20 3/20 yards

4 0
3 years ago
Please Help Now........
Bess [88]
Ok so 
what we do is
how much greater=wasted space=cylindervolume-conevolume

volume of a cinlinder=hpir^2
volume of a cone=(1/3)hpir^2
we can alread sybsitute something
(3/3)hpir^2-(1/3)hpir^2=(2/3)hpir^2
so wasted space=(2/3)hpir^2

diameter=4
d=2r
d/2=r
4/2=2=r

and 6=height
so 
2/3(6)(3.14)(2^2)
4(3.14)(4)
16(3.14)
50.24 in^3 wasted

5 0
3 years ago
2) If a spider can move 1/9 of a mile every hour, then how many hours would it take
Vinvika [58]
72 hours because if you keep counting up by NInes 8 times you will hit 72
4 0
3 years ago
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