Answer:
correct option is d. $242.81
Step-by-step explanation:
given data
APR = 25.5% = 
= 2.125
paid = $3,729
solution
we get here finance charge on the 1st month by multiplying 3,729 and now adding it to existing balance
so we get finance charge for the second and third months similarly as
APR ÷ 100 = 
= 0.02125
so 1st
= $3,729 × 0.02125
= 79.25
and
$3,729 + $79.25 = $3808.24
so for next
= $3808.24 × 0.02125
= 80.93
and
$3808.24 + $80.93 = $3889.17
so for next
= $3889.17 × 0.02125
= 82.64
and
$3889.17 + $ 82.64 = $3971.81
so
finance
charge = 3971.81 - 3729
finance
charge = 242.81
so correct option is d. $242.81
a) 
because it is equal to the area of the shaded region between X=4 and X=6, and the probability that X falls within some interval is given by the area under the PDF.
b) 
because the shaded region is a rectangle of height 1/5 (by virtue of X following a uniform distribution over the interval [2, 7], which has length 5).
Answer:
The value of Car B will become greater than the value of car A during the fifth year.
Step-by-step explanation:
Note: See the attached excel file for calculation of beginning and ending values of Cars A and B.
In the attached excel file, the following are used:
Annual Depreciation expense of Car A = Initial value of Car A * Depreciates rate of Car A = 30,000 * 20% = 6,000
Annual Depreciation expense of Car B from Year 1 to Year 6 = Initial value of Car B * Depreciates rate of Car B = 20,000 * 15% = 3,000
Annual Depreciation expense of Car B in Year 7 = Beginning value of Car B in Year 7 = 2,000
Conclusion
Since the 8,000 Beginning value of Car B in Year 5 is greater than the 6,000 Beginning value of Car A in Year 5, it therefore implies that the value Car B becomes greater than the value of car A during the fifth year.
Answer:
- North Middle School = 10 students
- Central Middle School = 6 students
- South Middle School = 4 students
Step-by-step explanation:
First calculate the total number of students in all the schools:
= 618 + 378 + 204
= 1,200 students
Use this number to calculate the proportion of the total population that a school so that this can then be used to determine the proportion of the 20 delegates they should sent.
North Middle school:
= 618/1,200 * 20
= 10 students
Central Middle School:
= 378 / 1,200 * 20
= 6 students
South Middle School:
= 204/1,200 * 20
= 4 students
