3 pounds for $40.99. For this deal you’re paying $13.66 per pound.
Ms Mess gave 2*100=200$
The Clerk gave 3*50=150$
200-150=50$
The end up paying 50-70= (-20$)
Not sure
Answer:
Step-by-step explanation:
What are u talking about
Answer:
We are given:
![\hat{p}=0.65](https://tex.z-dn.net/?f=%5Chat%7Bp%7D%3D0.65)
Margin of error ![E=0.02](https://tex.z-dn.net/?f=E%3D0.02)
Confidence level = 0.99
We need to find the sample size to estimate the proportion of people who carry the TAS2R388 gene.
The formula for finding the sample size is:
![n=\hat{p} (1-\hat{p})\left (\frac{z_{\frac{0.01}{2}}}{E} \right )^{2}](https://tex.z-dn.net/?f=n%3D%5Chat%7Bp%7D%20%281-%5Chat%7Bp%7D%29%5Cleft%20%28%5Cfrac%7Bz_%7B%5Cfrac%7B0.01%7D%7B2%7D%7D%7D%7BE%7D%20%5Cright%20%29%5E%7B2%7D)
Where:
is the critical value at 0.01 significance level.
Therefore, the required sample size is:
![n=0.65(1-0.65) \left(\frac{2.576}{0.02} \right)^{2}](https://tex.z-dn.net/?f=n%3D0.65%281-0.65%29%20%5Cleft%28%5Cfrac%7B2.576%7D%7B0.02%7D%20%5Cright%29%5E%7B2%7D)
![=0.2275 \times 16589.44](https://tex.z-dn.net/?f=%3D0.2275%20%5Ctimes%2016589.44)
![=3774.1 \approx 3774](https://tex.z-dn.net/?f=%3D3774.1%20%5Capprox%203774)
Therefore, the required sample size is 3774