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3 years ago

What is 50 over 30 reduced fraction please?

Mathematics

1 answer:

LekaFEV [45]3 years ago

7 0

1 2/3 is the answerrrrrrr

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3 years ago

Identify the value of x and the length of each secant segment.

uranmaximum [27]

Answer:

x=7; NL=12; NP+20

Step-by-step explanation:

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3 years ago

I need help with D only. Finding the probability of selecting someone between 20 and 34 years old.

Hunter-Best [27]

The answer is 14% because that's the amount between 20 and 34 and your trying to find the percent between those two

4 0

2 years ago

Read 2 more answers

2. On the snow day, 8 kids from the neighbor-

andre [41]

Answer: 30 buttons

Step-by-step explanation:

If there were 8 kids, and 7 more joined, then there were 15 kids making snowmen (8+7 = 15). Each child used 2 buttons for the eyes, so 30 buttons were used (15 x2 = 30). This is assuming no other buttons were used on the snowmen for anything else

5 0

2 years ago

What are the minimum, first quartile, median, third quartile, and maximum of the data set? 2, 13, 17, 14, 9, 3, 16, 12

Alex777 [14]

So before anything, rearrange the data so that it's in ascending order: {2,3,9,12,13,14,16,17}

Next, the minimum and maximum are as they seem: the smallest and largest numbers in the data. Looking at our data, 2 is our minimum and 17 is our maximum.

Next, to find the median, find the number that is in the middle of the data set. If there isn't one number in the middle, find the average of the two middle numbers to get your median:

$\{2,3,9,\overbrace{\boxed{12,13,}}^{\textsf{middle numbers}}14,16,17\}\\\\\frac{12+13}{2}\\\\\frac{25}{2}\\\\12.5$

The median is 12.5.

Next, to find the first quartile, or the lower quartile, find the "median" of the numbers to the left of the median.

$\overbrace{\{2,\boxed{3,9,}12,}^{\textsf{left of median}}13,14,16,17\}\\\\\frac{3+9}{2}\\\\\frac{12}{2}\\\\6$

The first quartile is 6.

Next, to find the third quartile, or the upper quartile, find the "median" of the numbers to the right of the median.

$\{2,3,9,12,\overbrace{13,\boxed{14,16,}17\}}^{\textsf{right of median}}\\\\\frac{14+16}{2}\\\\\frac{30}{2}\\\\15$

The third quartile is 15.

3 0

3 years ago