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2 years ago

2. On the snow day, 8 kids from the neighbor-

Mathematics

1 answer:

andre [41]2 years ago

5 0

Answer: 30 buttons

Step-by-step explanation:

If there were 8 kids, and 7 more joined, then there were 15 kids making snowmen (8+7 = 15). Each child used 2 buttons for the eyes, so 30 buttons were used (15 x2 = 30). This is assuming no other buttons were used on the snowmen for anything else

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Write as a fraction.

lesantik [10]

Answer:

the answer is 5/8

Step-by-step explanation:

8 0

3 years ago

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HELP! Find the value of sin 0 if tan 0 = 4; 180 < 0< 270

BabaBlast [244]

Hi there! Use the following identities below to help with your problem.

$\large \boxed{sin \theta = tan \theta cos \theta} \\ \large \boxed{tan^{2} \theta + 1 = {sec}^{2} \theta}$

What we know is our tangent value. We are going to use the tan²θ+1 = sec²θ to find the value of cosθ. Substitute tanθ = 4 in the second identity.

$\large{ {4}^{2} + 1 = {sec}^{2} \theta } \\ \large{16 + 1 = {sec}^{2} \theta } \\ \large{ {sec}^{2} \theta = 17}$

As we know, sec²θ = 1/cos²θ.

$\large \boxed{sec \theta = \frac{1}{cos \theta} } \\ \large \boxed{ {sec}^{2} \theta = \frac{1}{ {cos}^{2} \theta} }$

And thus,

$\large{ {cos}^{2} \theta = \frac{1}{17}} \\ \large{cos \theta = \frac{ \sqrt{1} }{ \sqrt{17} } } \\ \large{cos \theta = \frac{1}{ \sqrt{17} } \longrightarrow \frac{ \sqrt{17} }{17} }$

Since the given domain is 180° < θ < 360°. Thus, the cosθ < 0.

$\large{cos \theta = \cancel\frac{ \sqrt{17} }{17} \longrightarrow cos \theta = - \frac{ \sqrt{17} }{17}}$

Then use the Identity of sinθ = tanθcosθ to find the sinθ.

$\large{sin \theta = 4 \times ( - \frac{ \sqrt{17} }{17}) } \\ \large{sin \theta = - \frac{4 \sqrt{17} }{17} }$

Answer

sinθ = -4sqrt(17)/17 or A choice.

4 0

3 years ago

In ΔKLM, k = 700 cm, l = 460 cm and ∠M=78°. Find the length of m, to the nearest centimeter.

pashok25 [27]

Answer:

753

Step-by-step explanation:

m^2 =700^2 +460^-2 −2(700)(460)cos78

m^2 = 490000+211600-2(700)(460)(0.207912)

m^2 = 490000+211600-133895.12889

m^2 = 567704.87111

m=753.462=753

6 0

3 years ago

The areas of two similar triangles are 72dm2 and 50dm2. The sum of their perimeters is 226dm. What is the perimeter of each of t

zloy xaker [14]

Answer:

103= p small

plarge = 123

Step-by-step explanation:

We know that the the ratio of the areas is the scale factor squared/

Larger triangle over smaller triangle

----- = scale factor ^2

simplify by dividing by 2 on top and bottom

----- = scale factor ^2

Take the square root of each side

sqrt(36)

-------------- = sqrt(scale factor ^2)

sqrt(25)

-------------- = scale factor

The ratio of the perimeters is the scale factor

p large 6

-------------- = ----------------

p small 5

Using cross products

6 p large = 5 p small

We know the sum is 226

p large + p small = 226

p large = 226 - p small

We have 2 equation and 2 unknowns

6 p large = 5 p small

Substitute for p large

6 (226 - p small) = 5 p small

1356 - 6 p small = 5 p small

Add 6 p small to each side

1356 = 11 p small

divide by 11

1356/11 = p small

P large = 226-1356/11

p large = 2486/11-1356/11

plarge = 1130/11

The solution requires whole number answers so

1356/11 = p small

123.27 which rounds to 123

plarge = 1130/11

plarge = 102.7272 = 103

6 0

3 years ago

24 : 18<br> In its simplest form

beks73 [17]

Answer:

4 : 3

Step-by-step explanation:

Because when you divide 24 by 6 and divide 18 by 6. It would be 4 : 3

7 0

3 years ago

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