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GaryK [48]
3 years ago
5

Anybody know the answer?

Mathematics
1 answer:
Yakvenalex [24]3 years ago
3 0
Note that 18=2(9) or 18=2(3)(3) or 18=2(3)^2.

Then log 18 = log 2(3)^2 = log 2 + 2log 3.
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Pls help stuck on big ideas math
beks73 [17]

Answer:

x = 15

Step-by-step explanation:

Substitute: -4/5x + 7 = -5

Rearrange unknown terms to the left side of the equation: -4/5x = -5 - 7

Calculate the sum or difference: -4/5x = -12

Divide both sides of the equation by the coefficient of variable: x = -12 × (-5/4)

Remove the parentheses: x = 12 × 5/4

Cross out the common factor: x = 3 × 5

Calculate the product or quotient: x = 15

So the answer is: x = 15

3 0
2 years ago
Need help to write equations for 5, 6 & 7
Nutka1998 [239]
5)
The x-values go up by 1: -2, -1, 0, 1, 2
The y values are always 3 times the previous value.
This is an exponential function.

y = a(b)^x

We need to find a and b.
Look at x = 0.
For x = 0, y = 4.

y = a(b)^x

4 = a(b)^0

Since b^0 = 1, this simplifies to

4 = a

Now we know a = 4. We have

y = 4(b)^x

Look at x = 1. For x = 1, y = 12.

12 = 4(b)^1

12 = 4b

b = 3

Now that we know a and b, we can write the function.

y = 4(3)^x

Now that you have the function written out, notice the following.
In the exponential equation we found, the number raised to x
is the number you multiply each y value to get the next y value.
In this case, each y value is 3 times the previous one, so you have 3^x.
The way you find "a" in the exponential equation is to look at the y-coordinate
when x = 0. When x = 0, b^x is 1, so b^x drops out, and you get "a" equal to
the y-value. In this case, when x = 0, y = 4, so "a" is 4.
With b = 3, and a = 4, you can quickly write:
y = 4(3)^x.
7 0
3 years ago
This one might not look familiar yet, but it's very similar to the distance problems you've already seen.
Debora [2.8K]

Answer:

176.

Step-by-step explanation:

5 0
3 years ago
2x squared + 9x=-5 i need to solve for x
In-s [12.5K]
2x^2+ 9x=-5 \\ \\2x^2 + 9x+5 =0 \\\\a=2, \ \ b=9 , \ \ c=5 \\\\\Delta =b^2-4ac = 9^2 -4\cdot 2\cdot 5 =  81-40=41 \\ \\x_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{-9-\sqrt{41}}{2\cdot 2 }=\frac{-9-\sqrt{41}}{ 4 }\\\\ x_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{-9+\sqrt{41}}{2\cdot 2 }=\frac{-9+\sqrt{41}}{4 }
3 0
3 years ago
Quick answer please ddd
ikadub [295]

Answer:

C

Step-by-step explanation:

It makes the most sense.

4 0
3 years ago
Read 2 more answers
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